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Mechanical Properties of Solids appeared 21 times across 3 years — 2.4% of Physics. This question is from Young's Modulus.

Year 2026 2025 2024 Total
Questions 4 9 8 21

Two wires A and B made of different materials of length 6.0 cm and 5.4 cm, respectively and area of cross sections 3.0 × 10⁻⁵ ~m² and 4.5 × 10⁻⁵ ~m² , respectively are stretched by the same magnitude under a given load. The ratio of the Young's modulus of A to that of B is x : 3. The value of x is ____.

Solution & Explanation

Related Formula
Y = StressStrain = (F / A)/(Δ / ) = (F )/(A Δ )
Core Logic

Since the wires are stretched by the same magnitude (Δ A = Δ B) under the same load (FA = FB), the Young's Modulus Y is proportional to ( )/(A).

Step 1: Setting up the Ratio
(YA)/(YB) = (( A)/( B)) ((AB)/(AA))

Substitute the given values: A = 6.0 ~cm B = 5.4 ~cm AA = 3.0 × 10⁻⁵ ~m² AB = 4.5 × 10⁻⁵ ~m²

Step 2: Calculation
(YA)/(YB) = ((6.0)/(5.4)) ( 4.5 × 10⁻⁵3.0 × 10⁻⁵) = ((60)/(54)) ((4.5)/(3.0)) = ((10)/(9)) ((1.5)/(1)) = (15)/(9) = (5)/(3)
Step 3: Finding x

Given ratio is x : 3.

(x)/(3) = (5)/(3) ⇒ x = 5
Pattern Recognition

Whenever "stretched by same magnitude under same load" appears, strip out F and Δ to leave Y ∝ / A.

Chapter Mix

Class 11 Physics: Mechanical Properties of Solids

Equation derivations for Young's Modulus
Equation derivations for Young's Modulus

Reference Study Guides

More Mechanical Properties of Solids Previous-Year Questions — Page 5

Q58 jee_main_2024_31_jan_morning Bulk Modulus
The depth below the surface of sea to which a rubber ball be taken so as to decrease its volume by 0.02% is ________ m. (Take density of sea water = 10³ kgm⁻³, Bulk modulus of rubber = 9 × 10⁸ Nm⁻², and g = 10 ms⁻²)
Numerical Answer. Answer: 18 to 18

Solution

Related Formula
β = (-Δ P)/((Δ V)/(V)) Δ P = ρ g h
Core Logic

The change in pressure Δ P is the hydrostatic pressure at depth h.

Δ P = -β (Δ V)/(V) ρ g h = -β (Δ V)/(V)
Step 2: Calculation

Given values: ρ = 10³ kg/m³ g = 10 m/s² β = 9 × 10⁸ N/m² (Δ V)/(V) = -0.02% = -(0.02)/(100)

Substitute into the equation:

10³ × 10 × h = - (9 × 10⁸) × (-(0.02)/(100)) 10⁴ × h = 9 × 10⁸ × 2 × 10⁻⁴ 10⁴ h = 18 × 10⁴ h = 18 m
Chapter Mix

Class 11 Physics: Mechanical Properties Of Solids Class 11 Physics: Mechanical Properties Of Fluids

More Mechanical Properties of Solids Questions — jee_main_2026_28_january_morning

Practice all Mechanical Properties of Solids previous-year questions →

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JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)