A thermodynamic system is taken through the cyclic process ABC as shown in the figure. The total work done by the system during the cycle ABC is ____ J.
A Pressure-Volume indicator diagram showing a clockwise triangular cycle ABC.
Numerical Answer Type:
Enter a numerical valueAnswer: 300 to 300+4 marks
Solution & Explanation
Related Formula
Wcycle = Area enclosed by the P-V cycle$$W_{\text{cycle}} = \text{Area enclosed by the P-V cycle}$$
Core Logic
In a P-V diagram, the work done in a cyclic process is equal to the area of the enclosed loop. Since the cycle ABC is clockwise (A arrow$\rightarrow$ B arrow$\rightarrow$ C arrow$\rightarrow$ A), the net work done by the system is positive.
Step 1: Calculate the Area
The shape ABC is a right-angled triangle.
Base of the triangle = Δ V = VC - VA = 5 - 2 = 3 m³$= \Delta V = V_C - V_A = 5 - 2 = 3 \text{ m}^3$
Height of the triangle = Δ P = PB - PC = 300 - 100 = 200 Pa$= \Delta P = P_B - P_C = 300 - 100 = 200 \text{ Pa}$
Always verify axis units (kPa, atm, Liters, cc) before blindly multiplying area. Here units are cleanly in standard SI (Pa and m³$m^3$), so 1 Pa · 1 m³ = 1 Joule$1 \text{ Pa} \cdot 1 \text{ m}^3 = 1 \text{ Joule}$.
Keywords:#thermodynamic system is taken through the cyclic process#JEE Main 2026 Evening Q47#Thermodynamics JEE Main 2026#Work Done in Cyclic Process JEE Main 2026#P-V diagram#Cyclic process#Triangle ABC#Pressure 100 Pa to 300 Pa#Volume 2 to 5 m3
More Thermodynamics Previous-Year Questions — Page 8
Qjee_main_2024_31_jan_morningIsobaric Process
The given figure represents two isobaric processes for the same mass of an ideal gas, then
A Volume vs Temperature (V-T) graph showing two straight lines starting from the origin representing distinct constant pressures P1 and P2.
A.P₂≥ P₁$\mathrm{P}_2\geq \mathrm{P}_1$
B.P₂ > P₁$\mathrm{P}_2 > \mathrm{P}_1$
C.P₁ = P₂$\mathrm{P_1 = P_2}$
D.P₁ > P₂$\mathrm{P}_1 > \mathrm{P}_2$
Solution
Related Formula
PV = nRT$PV = nRT$
Core Logic
From the Ideal Gas Law:
V = ((nR)/(P)) T$$V = \left(\frac{nR}{P}\right) T$$
In a V-T$V-T$ graph, the equation of the line represents y = mx$y = mx$, where the slope m$m$ is:
Practice past-year questions one chapter at a time. Pick an exam → subject → chapter and get every PYQ for that topic — pulled together from all past papers — with the chapter's key formulas alongside.
