NEET · Physics —

Thermodynamics appeared 1 time across 1 year — 2.2% of Physics. This question is from First Law of Thermodynamics.

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Questions 1 1
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An electric heater supplies heat to a system at a rate of 100 ~W. If the system performs work at a rate of 75 ~J/s, then the rate at which internal energy increases will be:

Solution & Explanation

Related Formula
Δ Q = Δ U + Δ W (dQ)/(dt) = (dU)/(dt) + (dW)/(dt)
Core Logic

Using the 1st Law of Thermodynamics expressed as rate of energy transfer: Given: Rate of heat supplied (dQ)/(dt) = 100 ~W = 100 ~J/s Rate of work done by system (dW)/(dt) = 75 ~J/s

Step 1: Calculate Internal Energy Rate
100 ~W = (dU)/(dt) + 75 ~W (dU)/(dt) = 100 ~W - 75 ~W = 25 ~W
Pattern Recognition

Heat supplied is positive input. Work done by the system is positive energy leaving. The remainder is purely stored as internal energy.

Chapter Mix

Class 11 Physics: Thermodynamics

Reference Study Guides

Thermodynamics

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Rankbit System
JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)