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Differential Equations appeared 46 times across 3 years — 5.3% of Mathematics. This question is from Integral Equations.

Year 2026 2025 2024 Total
Questions 13 17 16 46

Let a differentiable function f satisfy the equation ∫₀³⁶f((tx)/(36))dt = 4α f(x). If y = f(x) is a standard parabola passing through the points (2, 1) and (-4, β), Then βα is equal to

Numerical Answer Type:
Enter a numerical value Answer: 64 to 64 +4 marks

Solution & Explanation

Related Formula

Newton-Leibniz Rule for differentiating under the integral sign:

(d)/(dx) ( ∫u(x)v(x) f(t) dt ) = f(v(x))· v'(x) - f(u(x))· u'(x)
Core Logic
Put (tx)/(36) = y ⇒ (x)/(36) dt = dy ⇒ dt = (36)/(x) dy

Limits: when t = 0, y = 0; when t = 36, y = x.

∫₀^x f(y) (36)/(x) dy = 4α f(x) ∫₀^x f(y) dy = (α x)/(9) f(x)
Step 1: Differentiating with respect to x
f(x) = (α)/(9) ( f(x) + x f'(x) ) f(x) (1 - (α)/(9)) = (α x)/(9) f'(x) (f'(x))/(f(x)) = ( (9)/(α) - 1 ) (1)/(x)
Step 2: Integration for Function
ln f(x) = ( (9)/(α) - 1 ) ln x + ln c f(x) = c x((9)/(α) - 1)

Given y = f(x) is a standard parabola (typically y² = 4ax or x² = 4ay). From the polynomial form, it implies degree 2.

(9)/(α) - 1 = 2 ⇒ (9)/(α) = 3 ⇒ α = 3

So, f(x) = c x².

Step 3: Point Substitution

Passes through (2, 1):

1 = c(2)² ⇒ 4c = 1 ⇒ c = (1)/(4)

Thus, y = (x²)/(4). Passes through (-4, β):

β = ((-4)²)/(4) = (16)/(4) = 4 β^α = 4³ = 64
Pattern Recognition

Integral equations of the form ∫ f(tx)dt inherently resolve by standardizing the boundary variable (tx → y) and differentiating, revealing an underlying homogeneous differential equation.

Chapter Mix

Class 12 Maths: Differential Equations Class 11 Maths: Conic Sections

Reference Study Guides

More Differential Equations Previous-Year Questions — Page 10

Q11 jee_main_2024_31_jan_morning Linear Differential Equations
Let y = y(x) be the solution of the differential equation (dy)/(dx) = (( x) + y)/( x( x - x x)), x in (0, (π)/(2)) satisfying the condition y((π)/(4)) = 2. Then, y((π)/(3)) is
  • A. √(3)(2 + ₑ√(3))
  • B. √(3)2(2 + ₑ 3)
  • C. √(3)(1 + 2 ₑ 3)
  • D. √(3)(2 + ₑ 3)

Solution

Core Logic
(dy)/(dx) = (( x)/( x) + y)/( x ((1)/( x) - ( ² x)/( x))) = ( x + y x)/( x (1 - ² x)) (dy)/(dx) = ( x + y x)/( x ² x) = ² x + (2y)/( 2x) (dy)/(dx) - 2 (2x)y = ² x
Step 1: Integrating Factor

This is an LDE of form (dy)/(dx) + Py = Q.

I.F. = e∫ -2 (2x) dx

Let 2x = t 2dx = dt.

I.F. = e-∫ t dt = e-ln| (t/2)| = e-ln| x| = (1)/(| x|)
Step 2: Solution of LDE
y(I.F.) = ∫ Q(I.F.) dx + C y(1)/( x) = ∫ ² x (1)/( x) dx + C

Let x = t ² x dx = dt.

y(1)/( x) = ∫ (dt)/(t) + C = ln| x| + C y = x(ln| x| + C)
Step 3: Boundary Value

Given y(π/4) = 2:

2 = 1(ln 1 + C) C = 2

Thus, y = x (ln| x| + 2). At x = π/3:

y(π/3) = √(3)(ln√(3) + 2)
Chapter Mix

Class 12 Maths: Differential Equations

More Differential Equations Questions — jee_main_2026_24_january_morning

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