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Thermodynamics appeared 36 times across 3 years — 4.2% of Physics. This question is from Isochoric Process and Heat Transfer.

Year 2026 2025 2024 Total
Questions 11 19 6 36

10 mole of an ideal gas is undergoing the process shown in the figure. The heat involved in the process from P₁ to P₂ is α Joule ( P₁ = 21.7Pa and P₂ = 30Pa , Cv = 21J / K.mol , R = 8.3J / mol.K ). The value of α is ____.
Isochoric Process and Heat Transfer diagram for Q43 - JEE Main 2026 Evening
A Pressure-Volume graph displaying an isochoric rise from P1 to P2 at constant V=1.

Solution & Explanation

Related Formula
Δ Q = n Cv Δ T

From Ideal Gas Law for Isochoric Process:

n R Δ T = Δ P · V
Core Logic

From the P-V graph, the process from P₁ to P₂ takes place at a constant volume V = 1 m³.

Step 1: Calculate Heat Involved
Δ Q = n Cv Δ T

Multiply and divide by R:

Δ Q = (Cv)/(R) · (nRΔ T) = (Cv)/(R) · (P₂ - P₁)V
Step 2: Substitution

Given Cv = 21 J/K· mol, R = 8.3 J/mol· K, P₂ = 30, P₁ = 21.7, and V = 1:

Δ Q = (21)/(8.3) × (30 - 21.7) × 1 Δ Q = (21)/(8.3) × 8.3 = 21 J
Pattern Recognition

For constant volume processes, Δ Q strictly scales with Δ P. Re-writing n Δ T as V Δ P / R circumvents calculating absolute temperatures entirely.

Chapter Mix

Class 11 Physics: Thermodynamics

Reference Study Guides

More Thermodynamics Previous-Year Questions — Page 8

Q jee_main_2024_31_jan_morning Isobaric Process
The given figure represents two isobaric processes for the same mass of an ideal gas, then
Isobaric Process diagram for Q38 - JEE Main 2024 Morning
A Volume vs Temperature (V-T) graph showing two straight lines starting from the origin representing distinct constant pressures P1 and P2.
  • A. P₂≥ P₁
  • B. P₂ > P₁
  • C. P₁ = P₂
  • D. P₁ > P₂

Solution

Related Formula

PV = nRT

Core Logic

From the Ideal Gas Law:

V = ((nR)/(P)) T

In a V-T graph, the equation of the line represents y = mx, where the slope m is:

Slope = (nR)/(P) Slope ∝ (1)/(P)

Thus, a higher slope corresponds to a lower pressure.

Step 2: Compare Slopes

From the given figure, the slope of line 2 is greater than the slope of line 1:

(Slope)₂ > (Slope)₁

Therefore, inversely: P₂ < P₁ or P₁ > P₂.

Pattern Recognition

In V-T graphs, steeper lines mean lower Pressure. In P-T graphs, steeper lines mean lower Volume. It's an inverse inverse slope relationship.

Chapter Mix

Class 11 Physics: Thermodynamics

More Thermodynamics Questions — jee_main_2026_24_january_evening

Practice all Thermodynamics previous-year questions →

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JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)