In hydrogen atom spectrum, (R arrow$R \rightarrow$ Rydberg's constant) A. the maximum wavelength of the radiation of Lyman series is (4)/(3R)$\frac{4}{3R}$ B. the Balmer series lies in the visible region of the spectrum C. the minimum wavelength of the radiation of Paschen series is (9)/(R)$\frac{9}{R}$ D. the minimum wavelength of Lyman series is (5)/(4R)$\frac{5}{4R}$ Choose the correct answer from the options given below:

Related Formula

Core Logic

Assess each statement using the Rydberg formula. Max wavelength corresponds to min energy (transition from n₁+1 → n₁$n_{1}+1 \to n_{1}$), and min wavelength corresponds to max energy (n₂ → ∞$n_{2} \to \infty$).

Step 1: Evaluate A and D (Lyman Series)

For Lyman series, n₁ = 1$n_{1} = 1$. Maximum wavelength (n₂ = 2$n_{2} = 2$):

Statement A is correct.

Minimum wavelength (n₂ = ∞$n_{2} = \infty$):

Statement D is incorrect.

Step 2: Evaluate B (Balmer Series)

Balmer series corresponds to transitions to n₁ = 2$n_{1} = 2$. These transitions primarily emit in the visible spectrum. Statement B is correct.

Step 3: Evaluate C (Paschen Series)

For Paschen series, n₁ = 3$n_{1} = 3$. Minimum wavelength (n₂ = ∞$n_{2} = \infty$):

Statement C is correct.

Step 4: Final Conclusion

Statements A, B, and C are correct.

Pattern Recognition

Sees: "minimum/maximum wavelength" → Max wavelength = adjacent orbital drop (n+1$n+1$ to n$n$). Min wavelength = drop from infinity (∞$\infty$ to n$n$).

Chapter Mix

Class 12 Physics: Atoms