One mole of an ideal diatomic gas expands from volume V to 2V isothermally at a temperature27°$27^{\circ}$ C and does W joule of work. If the gas undergoes same magnitude of expansion adiabatically from 27°$27^{\circ}$ C doing the same amount of work W, then its final temperature will be (close to) ____ °${}^{\circ}$ C.
For a diatomic gas, γ = 1.4$\gamma = 1.4$.
Given initial temperature T = 27°C = 300 K$T = 27^{\circ}\mathrm{C} = 300 \, \mathrm{K}$.
Since Wisothermal = Wadiabatic$W_{\text{isothermal}} = W_{\text{adiabatic}}$, we equate the two expressions.
Equating the work of two different processes links the log expansion to the temperature drop. Recognize diatomic gas instantly means γ = 1.4$\gamma = 1.4$, providing the 0.4$0.4$ divisor.
Practice past-year questions one chapter at a time. Pick an exam → subject → chapter and get every PYQ for that topic — pulled together from all past papers — with the chapter's key formulas alongside.
