An air bubble of volume 2.9 cm³$2.9 \, \mathrm{cm}^{3}$ rises from the bottom of a swimming pool of 5 m deep. At the bottom of the pool water temperature is 17 °C$17 \, ^{\circ}\mathrm{C}$ . The volume of the bubble when it reaches the surface, where the water temperature is 27 °C$27 \, ^{\circ}\mathrm{C}$ , is ____ cm³$\mathrm{cm}^{3}$ .
(g = 10 m/s²$g = 10 \, \mathrm{m/s}^{2}$ , density of water = 10³ kg/m³$10^{3} \, \mathrm{kg/m}^{3}$ , and 1 atm pressure is 10⁵ Pa$10^{5} \, \mathrm{Pa}$ )
For an air bubble rising in water, the number of moles of gas remains constant.
P₁$P_1$ = Pressure at bottom = Patm + ρ gh$P_{\text{atm}} + \rho gh$T₁$T_1$ = Temperature at bottom = 17°C = 290 K$17^{\circ}\mathrm{C} = 290 \, \mathrm{K}$V₁$V_1$ = 2.9 cm³$2.9 \, \mathrm{cm}^3$
P₂$P_2$ = Pressure at surface = Patm$P_{\text{atm}}$T₂$T_2$ = Temperature at surface = 27°C = 300 K$27^{\circ}\mathrm{C} = 300 \, \mathrm{K}$
Standard combined gas law application. Always remember to convert Celsius to Kelvin and carefully compute gauge pressure plus atmospheric pressure for the submerged state.
Chapter Mix
Class 11 Physics: Kinetic Theory of Gases
Class 11 Physics: Mechanical Properties of Fluids
The average translational kinetic energy of any gas molecule depends only on the absolute temperature of the gas and is independent of the nature or mass of the gas.
For 1 mole of any ideal gas, the average translational kinetic energy is (3)/(2)RT$\frac{3}{2}RT$. Therefore, at a given temperature, the kinetic energy parameter is uniform across all ideal gases.
Pattern Recognition
Temperature is directly proportional to average translational kinetic energy. If T is constant, KE is constant for all gases regardless of mass.
Chapter Mix
Class 11 Physics: Kinetic Theory
More Kinetic Theory of Gases Questions — jee_main_2026_23_january_evening
Practice past-year questions one chapter at a time. Pick an exam → subject → chapter and get every PYQ for that topic — pulled together from all past papers — with the chapter's key formulas alongside.