JEE Main · Physics ↓ Falling

Work, Energy and Power appeared 31 times across 3 years — 3.6% of Physics. This question is from Conservative Forces and Work Done.

Year 2026 2025 2024 Total
Questions 8 15 8 31

Given below are two statements : Statement I: An object moves from position r₁ to position r₂ under a conservative force field F. The work done by the force is W = -∫_r₁^r₂ F · dr. Statement II : Any object moving from one location to another location can follow infinite number of paths. Therefore, the amount of work done by the object changes with the path it follows for a conservative force. In the light of the above statements, choose the correct answer from the options given below :

Solution & Explanation

Related Formula
W = ∫r₁r₂ F · d r ∮ Fcons · d r = 0
Core Logic

Evaluating Statement I: Work done by a force is defined as W = +∫r₁r₂ F · d r. The negative sign represents potential energy change (Δ U = -W), not work done itself. Thus Statement I is incorrect.

Evaluating Statement II: For a conservative force, work done depends ONLY on initial and final positions, independent of the path taken. Thus Statement II is incorrect.

Step 1: Final Conclusion

Both Statement I and Statement II are false.

Pattern Recognition

Conservative force definition: Work done is path-independent (W depends only on end points). Formula for work is +∫ F · d r.

Chapter Mix

Class 11 Physics: Work, Energy and Power

Reference Study Guides

More Work, Energy and Power Previous-Year Questions — Page 7

Q49 jee_main_2024_31_jan_morning Conservation Of Momentum
An artillery piece of mass M₁ fires a shell of mass M₂ horizontally. Instantaneously after the firing, the ratio of kinetic energy of the artillery and that of the shell is :
  • A. M₁ / (M₁ + M₂)
  • B. (M₂)/(M₁)
  • C. M₂ / (M₁ + M₂)
  • D. (M₁)/(M₂)

Solution

Related Formula
KE = (p²)/(2m)
Core Logic

By conservation of linear momentum (since no external horizontal force acts on the system):

0 = M₁ v₁ + M₂ v₂ | p₁| = | p₂| = p

Both the artillery and the shell acquire the exact same magnitude of momentum during firing.

Step 2: Kinetic Energy Ratio

The kinetic energy is related to momentum by KE = (p²)/(2m). Since p is identical for both bodies:

KE ∝ (1)/(m)

Therefore, the ratio of kinetic energy of the artillery (M₁) to the shell (M₂) is:

KE₁KE₂ = ((p²)/(2M₁))/((p²)/(2M₂)) = (M₂)/(M₁)
Chapter Mix

Class 11 Physics: Work, Energy And Power

More Work, Energy and Power Questions — jee_main_2026_22_january_evening

Practice all Work, Energy and Power previous-year questions →

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JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)