The value of int_-pi/6^pi/6left(fracpi+4x^111-sin(|x|+pi/6)right)dx is equal to

Solution & Explanation

### Related Formula int_-a^a f(x) dx = int_0^a [f(x) + f(-x)] dx ### Core Logic Let I = int_-pi/6^pi/6fracpi+4x^111-sin(|x|+pi/6)dx. The denominator 1 - sin(|x| + pi/6) is an even function. The numerator can be split into an even part (pi) and an odd part (4x^11). int_-a^a frac4x^111-sin(|x|+pi/6) dx = 0 quad text(Since integrand is odd) ### Step 1: Simplify to Even Integral We are left with the even part: I = int_-pi/6^pi/6 fracpi1 - sin(|x| + pi/6) dx Using even function property int_-a^a f(x) dx = 2 int_0^a f(x) dx: I = 2pi int_0^pi/6 frac11 - sin(x + pi/6) dx ### Step 2: Substitution Let t = x + fracpi6 Rightarrow dt = dx. Limits: when x = 0 Rightarrow t = pi/6, when x = pi/6 Rightarrow t = pi/3. I = 2pi int_pi/6^pi/3 fracdt1 - sin t ### Step 3: Solve the Integral Rationalize the denominator: I = 2pi int_pi/6^pi/3 frac1 + sin t(1 - sin t)(1 + sin t) dt I = 2pi int_pi/6^pi/3 frac1 + sin tcos^2 t dt I = 2pi int_pi/6^pi/3 (sec^2 t + sec t tan t) dt Integrate directly: I = 2pi left[ tan t + sec t right]_pi/6^pi/3 Evaluate limits: Upper limit (pi/3): tan(pi/3) + sec(pi/3) = sqrt3 + 2 Lower limit (pi/6): tan(pi/6) + sec(pi/6) = frac1sqrt3 + frac2sqrt3 = frac3sqrt3 = sqrt3 I = 2pi [(sqrt3 + 2) - sqrt3] = 2pi (2) = 4pi ### Pattern Recognition Symmetric limits [-a, a] instantly demand testing for odd/even parity. Any mixed polynomial like c + k x^textodd over an even denominator guarantees the odd power term strictly vanishes, halving calculation time. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Maths: Definite Integration Class 11 Maths: Trigonometric Functions

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