Given below are some of the statements about textMn and textMn_2textO_7. Identify the correct statements: A. Mn forms the oxide textMn_2textO_7 in which Mn is in its highest oxidation state. B. Oxygen stabilizes the Mn in higher oxidation states by forming multiple bonds with Mn. C. textMn_2textO_7 is an ionic oxide. D. The structure of textMn_2textO_7 consists of one bridged oxygen. Choose the correct answer from the options given below:

Solution & Explanation

### Core Logic - A is correct: textMn_2textO_7 features Mn in +7 state (its highest oxidation state). - B is correct: Oxygen stabilizes high oxidation states via multiple bonding. - C is incorrect: textMn_2textO_7 is a covalent green oil/oxide, not ionic. - D is correct: Structure consists of two textMnO_4 tetrahedra sharing one bridging oxygen atom (textO_3textMn-textO-textMnO_3). ### Step 1: Final Conclusion Statements A, B and D are correct, matching option (2). ### Pattern Recognition Sees: Properties and bonding of transition metal oxides like textMn_2textO_7. Trap: Assuming high oxidation state oxides of transition metals are ionic. ### Chapter Mix Class 12 Chemistry: The d- and f-Block Elements
Structure of Mn2O7 for Q66 - JEE Main 2026 Evening
Structure of Mn2O7 for Q66 - JEE Main 2026 Evening

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