By usual analysis, 1.00g of compound (X) gave 1.79g of magnesium pyrophosphate. The percentage of phosphorus in compound (X) is: (nearest integer) (Given, molar mass in textg mol^-1: textO = 16, textMg = 24, textP = 31)

Solution & Explanation

### Related Formula \% text of textP = fractextMoles of textMg_2textP_2textO_7 times 2 times 31textMass of compound times 100 ### Core Logic Molar mass of textMg_2textP_2textO_7 = 2(24) + 2(31) + 7(16) = 48 + 62 + 112 = 222 text g/mol. textPercentage of P = fracleft(frac1.79222 times 2 times 31right)1 times 100 = 49.99\% approx 50\% ### Step 1: Final Calculation Rounding to the nearest integer gives 50. ### Pattern Recognition Sees: Gravimetric analysis involving magnesium pyrophosphate. Trap: Forgetting the factor of 2 for phosphorus atoms in textMg_2textP_2textO_7. ### Chapter Mix Class 11 Chemistry: Some Basic Concepts of Chemistry

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