Aqueous HCl reacts with MnO2(s) to form MnCl2(aq), Cl2(g) and H2O(l). What is the weight (in g) of Cl2 liberated when 8.7 g of MnO2(s) is reacted with excess aqueous HCl solution? (Given Molar mass in g mol-1: Mn = 55, Cl = 35.5, O = 16, H = 1)

Balanced reaction: Molar mass of MnO2 = 55 + 32 = 87 g/mol. Moles of MnO2 = (8.7/87) = 0.1 mol. From stoichiometry, 1 mole of MnO2 produces 1 mole of Cl2. Therefore, moles of Cl2 produced = 0.1 mol. Weight of Cl2 = 0.1 x 71 = 7.1 g. Sees: stoichiometry calculation with manganese dioxide and hydrochloric acid. Trap: Forgetting stoichiometric coefficients for chlorine gas. Class 11 Chemistry: Redox Reactions

Aqueous HCl reacts with MnO2(s) to form MnCl2(aq), Cl2(g) and H2O(l). What is the weight (in g) of Cl2 liberated when 8.7 g of MnO2(s) is reacted with excess aqueous HCl solution? (Given Molar mass in

Balanced reaction: Molar mass of MnO2 = 55 + 32 = 87 g/mol. Moles of MnO2 = (8.7/87) = 0.1 mol. From stoichiometry, 1 mole of MnO2 produces 1 mole of Cl2. Therefore, moles of Cl2 produced = 0.1 mol. Weight of Cl2 = 0.1 x 71 = 7.1 g. Sees: stoichiometry calculation with manganese dioxide and hydrochloric acid. Trap: Forgetting stoichiometric coefficients for chlorine gas. Class 11 Chemistry: Redox Reactions

Aqueous HCl reacts with MnO2(s) to form MnCl2(aq), Cl2(g) and H2O(l). What is the weight (in g) of Cl2 liberated when 8.7 g of MnO2(s) is reacted with excess aqueous HCl solution? (Given Molar mass in g mol-1: Mn = 55, Cl = 35.5, O = 16, H = 1)

Balanced reaction: Molar mass of MnO2 = 55 + 32 = 87 g/mol. Moles of MnO2 = (8.7/87) = 0.1 mol. From stoichiometry, 1 mole of MnO2 produces 1 mole of Cl2. Therefore, moles of Cl2 produced = 0.1 mol. Weight of Cl2 = 0.1 x 71 = 7.1 g. Sees: stoichiometry calculation with manganese dioxide and hydrochloric acid. Trap: Forgetting stoichiometric coefficients for chlorine gas. Class 11 Chemistry: Redox Reactions

Aqueous HCl reacts with MnO2(s) to form MnCl2(aq), Cl2(g) and H2O(l). What is the weight (in g) of Cl2 liberated when 8.7 g of MnO2(s) is reacted with excess aqueous HCl solution? (Given Molar mass in

Balanced reaction: Molar mass of MnO2 = 55 + 32 = 87 g/mol. Moles of MnO2 = (8.7/87) = 0.1 mol. From stoichiometry, 1 mole of MnO2 produces 1 mole of Cl2. Therefore, moles of Cl2 produced = 0.1 mol. Weight of Cl2 = 0.1 x 71 = 7.1 g. Sees: stoichiometry calculation with manganese dioxide and hydrochloric acid. Trap: Forgetting stoichiometric coefficients for chlorine gas. Class 11 Chemistry: Redox Reactions

Aqueous HCl reacts with MnO2(s) to form MnCl2(aq), Cl2(g) and H2O(l). What is the weight (in g) of Cl2 liberated when…

Solution & Explanation

### Related Formula

textMoles = fractextGiven MasstextMolar Mass

### Core Logic Balanced reaction:

textMnO_2 + 4textHCl rightarrow textMnCl_2 + textCl_2 + 2textH_2textO

Molar mass of

textMnO_2 = 55 + 32 = 87 text g/mol

. Moles of

textMnO_2 = frac8.787 = 0.1 text mol

. From stoichiometry, 1 mole of

textMnO_2

produces 1 mole of

textCl_2

. Therefore, moles of

textCl_2

produced =

0.1 text mol

. ### Step 1: Final Calculation Weight of

textCl_2 = 0.1 times 71 = 7.1 text g

. ### Pattern Recognition Sees: stoichiometry calculation with manganese dioxide and hydrochloric acid. Trap: Forgetting stoichiometric coefficients for chlorine gas. ### Chapter Mix Class 11 Chemistry: Redox Reactions

Solution & Explanation

Reference Study Guides

More Redox Reactions Questions — jee_main_2026_21_jan_evening

We Map Every Repeating Question in Competitive Exams.

Select Your Target Exam

Full Mock Test Hub

Topic-wise Practice Hub

Exam Analysis Tools

Chapter Weightage & Trends

Topic-wise Practice Hub

JEE Main Exam Papers

Chapter Weightage Board

Formula Recognition

Exam Questions

Select an Exam

Solution & Explanation

Reference Study Guides

More Redox Reactions Questions — jee_main_2026_21_jan_evening

We Map Every Repeating Question in Competitive Exams.

Select Your Target Exam

Full Mock Test Hub

Topic-wise Practice Hub

Exam Analysis Tools

Chapter Weightage & Trends

Topic-wise Practice Hub

JEE Main Exam Papers

Chapter Weightage Board

Formula Recognition

Exam Questions

Select an Exam

Welcome back