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Mechanical Properties of Fluids appeared 32 times across 3 years — 3.7% of Physics. This question is from Pascal\'s Law.

Year 2026 2025 2024 Total
Questions 9 15 8 32

In a hydraulic lift, the surface area of the input piston is 6cm² and that of the output piston is 1500cm² . If 100N force is applied to the input piston to raise the output piston by 20cm , then the work done is ________ kJ.

Numerical Answer Type:
Enter a numerical value Answer: 5 to 5 +4 marks

Solution & Explanation

Related Formula
W = F₁ · s₁ = F₂ · s₂
Core Logic

By conservation of liquid volume displacement during output piston elevation :

A₁ · s₁ = A₂ · s₂ 6 · s₁ = 1500 · 20 s₁ = 5000 cm = 50 m

Work performed on input boundary matches :

W = F₁ · s₁ = 100 N · 50 m = 5000 J = 5 kJ

Alternatively via output force profile calculation:

Hydraulic lift work diagram allocation
Hydraulic lift work diagram allocation

F₂ = F₁ (A₂)/(A₁) = 100 (1500)/(6) = 25000 N W = F₂ · s₂ = 25000 · 0.2 = 5000 J = 5 kJ
Chapter Mix

Class 11 Physics: Mechanical Properties of Fluids

Hydraulic lift work diagram allocation
Hydraulic lift work diagram allocation

More Mechanical Properties of Fluids Previous-Year Questions

Q jee_main_2026_21_jan_morning Bernoulli's Principle
Water flows through a horizontal tube as shown in the figure. The difference in height between the water columns in vertical tubes is 5 cm and the area of cross-sections at A and B are 6 cm² and 3 cm² respectively. The rate of flow will be ____ cm³/s. (take g = 10 m/s²)
Bernoulli's Principle diagram for Q29 - JEE Main 2026 Morning
The figure illustrates a Venturi meter setup with water flowing through a variable cross-section tube.
  • A. 200√(3)
  • B. 200√(6)
  • C. 200√(3)
  • D. 100√(3)

Solution

Related Formula
A₁ V₁ = A₂ V₂ P₁ + (1)/(2)ρ V₁² = P₂ + (1)/(2)ρ V₂² P₁ - P₂ = ρ g h
Core Logic

From the continuity equation between A and B:

AAVA = ABVB 6VA = 3VB VB = 2VA

Applying Bernoulli's equation between A and B for a horizontal pipe:

PA + (1)/(2)ρ VA² = PB + (1)/(2)ρ VB² PA - PB = (1)/(2)ρ(VB² - VA²)

Since the height difference is h = 5 cm = 0.05 m, the pressure difference is ρ gh.

ρ g × 0.05 = (1)/(2)ρ( (2VA)² - VA² ) g × 0.05 = (1)/(2)(3VA²)
Step 1: Calculate Velocity and Volume Flow Rate

Solving for VA:

VA = √((2 × 10 × 0.05)/(3)) = √((1)/(3)) = 1√(3) m/s VA = 100√(3) cm/s

Volume flow rate Q = AA VA:

Q = 6 cm² × 100√(3) cm/s = 600√(3) = 200√(3) cm³/s
Pattern Recognition

In a horizontal Venturi meter, substituting V₂ = V₁ (A₁/A₂) directly into ρ g h = (1)/(2)ρ (V₂² - V₁²) is the standard path. Working in CGS vs MKS units requires careful tracking; convert VA to cm/s before multiplying by AA in cm².

Chapter Mix

Class 11 Physics: Mechanical Properties of Fluids

Q38 jee_main_2026_21_jan_evening Surface Tension
Surface tension of two liquids (having same densities), T₁ and T₂, are measured using capillary rise method utilizing two tubes with inner radii of r₁ and r₂ where r₁ > r₂. The measured liquid heights in these tubes are h₁ and h₂ respectively. [Ignore the weight of the liquid about the lowest point of miniscus]. The heights h₁ and h₂ and surface tensions T₁ and T₂ satisfy the relation :
  • A. h₁ < h₂ and T₁ = T₂
  • B. h₁ = h₂ and T₁ = T₂
  • C. h₁ > h₂ and T₁ = T₂
  • D. h₁ > h₂ and T₁ < T₂

Solution

Related Formula
h = (2T θ)/(ρ g r)
Core Logic

Since we are assessing surface tension T as a property of the liquids, the question intends to compare liquids that are identical (implying T₁ = T₂ and same density).

Capillary rise formula block for Q38 - JEE Main 2026 Evening
Capillary rise formula block for Q38 - JEE Main 2026 Evening
By Jurin's Law, for identical liquids, the height of capillary rise is inversely proportional to the radius of the tube:

h ∝ (1)/(r)
Step 1: Final Conclusion

Given r₁ > r₂, the inverse proportionality directly implies that the liquid will rise less in the wider tube. Therefore, h₁ < h₂ and naturally T₁ = T₂ for the intrinsic property.

Pattern Recognition

Wider tubes (r large) cause lower capillary rises (h small). h ∝ 1/r is a foundational inverse relationship in capillary action.

Chapter Mix

Class 11 Physics: Mechanical Properties of Fluids

Q47 jee_main_2026_21_jan_evening Terminal Velocity
The terminal velocity of a metallic ball of radius 6 mm in a viscous fluid is 20 cm/s. The terminal velocity of another ball of same material and having radius 3 mm in the same fluid will be ________ cm/s.
Numerical Answer. Answer: 5 to 5

Solution

Related Formula
vT = (2r² g)/(9η) (σ - ρ)
Core Logic

For balls of the same material falling through the same fluid, all terms in the terminal velocity equation except the radius r are constant. Therefore, vT ∝ r².

Step 1: Setting up the Ratio
((vT)₁)/((vT)₂) = ((r₁)/(r₂))²

Substituting the given values: r₁ = 6 mm, (vT)₁ = 20 cm/s r₂ = 3 mm

Step 2: Final Conclusion
(20)/((vT)₂) = ((6)/(3))² (20)/((vT)₂) = 2² = 4 (vT)₂ = (20)/(4) = 5 cm/s
Pattern Recognition

Terminal velocity is directly proportional to the square of the radius. Halving the radius (6 → 3) will drop the terminal velocity by a factor of 1/4.

Chapter Mix

Class 11 Physics: Mechanical Properties of Fluids

Q33 jee_main_2026_22_january_morning Pascal's Law and Surface Tension
Given below are two statements: Statement I : Pressure of fluid is exerted only on a solid surface in contact as the fluid-pressure does not exist everywhere in a still fluid. Statement II: Excess potential energy of the molecules on the surface of a liquid, when compared to interior, results in surface tension. In the light of the above statements, choose the correct answer from the options given below:
  • A. Statement I is true but Statement II is false
  • B. Both Statement I and Statement II are false
  • C. Both Statement I and Statement II are true
  • D. Statement I is false but Statement II is true

Solution

Related Formula
P = (F)/(A), Surface Tension ∝ Δ U
Core Logic

According to Pascal's law, pressure exists at every point in a liquid at rest, not just at boundaries. Thus, Statement I is false.

For interior molecules, net cohesive forces are zero, whereas surface molecules possess excess potential energy leading to surface tension. Thus, Statement II is correct.

Pattern Recognition

Sees: Fluid pressure definition + surface tension origin. Shortcut: Recall Pascal's law (pressure everywhere) and surface energy excess. Check: Matches option (4). ✓

Chapter Mix

Class 11 Physics: Mechanical Properties of Fluids

Q34 jee_main_2026_22_january_evening Capillarity and Surface Tension
When a part of a straight capillary tube is placed vertically in a liquid, the liquid raises up to certain height h. If the inner radius of the capillary tube, density of the liquid and surface tension of the liquid decrease by 1 % each, then the height of the liquid in the tube will change by ____%.
  • A. -1
  • B. +3
  • C. -3
  • D. +1

Solution

Related Formula
h = (2T θ)/(ρ g r) (Δ h)/(h)% = (Δ T)/(T)% - (Δ ρ)/(ρ)% - (Δ r)/(r)%
Core Logic

Applying fractional error analysis to the capillary rise formula:

(Δ h)/(h)% = (-1%) - (-1%) - (-1%) (Δ h)/(h)% = -1 + 1 + 1 = +1%

Capillary tube rise calculation diagram for Q34 - JEE Main 2026 Evening
Capillary tube rise calculation diagram for Q34 - JEE Main 2026 Evening

Step 1: Final Conclusion

The height of the liquid in the tube increases by +1%.

Pattern Recognition

Percentage error in capillary rise: h ∝ (T)/(ρ r). Decreasing numerator T by 1% reduces h by 1% (-1%). Decreasing denominators ρ and r by 1% each increases h by 1% twice (+1% + 1%). Net change: -1 + 1 + 1 = +1%.

Chapter Mix

Class 11 Physics: Mechanical Properties of Fluids

More Mechanical Properties of Fluids Questions — jee_main_2025_29_jan_morning

Practice all Mechanical Properties of Fluids previous-year questions →

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