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Differential Equations appeared 46 times across 3 years — 5.3% of Mathematics. This question is from Linear Differential Equations.

Year 2026 2025 2024 Total
Questions 13 17 16 46

If for the solution curve y = f(x) of the differential equation (dy)/(dx) + ( x)y = (2 + x)/((1 + 2 x)²), x in ((-π)/(2), (π)/(2)), f((π)/(3)) = √(3)10, then f((π)/(4)) is equal to:

Solution & Explanation

Related Formula

Integrating factor (I.F.) for a linear differential equation (dy)/(dx) + Py = Q:

I.F. = e∫ P dx

General solution:

y · (I.F.) = ∫ Q · (I.F.) dx
Core Logic

Given P = x, compute Integrating Factor:

I.F. = e∫ x dx = eln( x) = x

Set up integrated expression solution layout:

y · x = ∫ (2 + x)/((1 + 2 x)²) · x dx = ∫ (2 x + 1)/(( x + 2)²) · dx
Step 1: Evaluate Integration with Half-Angle Substitutions

Using tangent half-angle substitution t = (x)/(2) transformations simplifies the integral loop structure down to:

y · x = (2)/(t + (3)/(t)) + C

Plugging entry condition parameters f((π)/(3)) = √(3)10 tracking t = 1√(3) explicitly isolates boundary condition constant C: C = 0

Step 2: Calculate Target Point Value

At target query point x = (π)/(4), half-angle parameters scale to t = √(2) - 1:

y · √(2) = 2√(2) - 1 + 3√(2) - 1 = 2(√(2) - 1)6 - 2√(2) y = 4 - √(2)14
Pattern Recognition

When integrating complex rational expressions involving trigonometric values, half-angle substitution methods (t = (x)/(2)) are standard for reducing polynomial degrees.

Chapter Mix

Class 12 Mathematics: Differential Equations

Reference Study Guides

More Differential Equations Previous-Year Questions — Page 10

Q11 jee_main_2024_31_jan_morning Linear Differential Equations
Let y = y(x) be the solution of the differential equation (dy)/(dx) = (( x) + y)/( x( x - x x)), x in (0, (π)/(2)) satisfying the condition y((π)/(4)) = 2. Then, y((π)/(3)) is
  • A. √(3)(2 + ₑ√(3))
  • B. √(3)2(2 + ₑ 3)
  • C. √(3)(1 + 2 ₑ 3)
  • D. √(3)(2 + ₑ 3)

Solution

Core Logic
(dy)/(dx) = (( x)/( x) + y)/( x ((1)/( x) - ( ² x)/( x))) = ( x + y x)/( x (1 - ² x)) (dy)/(dx) = ( x + y x)/( x ² x) = ² x + (2y)/( 2x) (dy)/(dx) - 2 (2x)y = ² x
Step 1: Integrating Factor

This is an LDE of form (dy)/(dx) + Py = Q.

I.F. = e∫ -2 (2x) dx

Let 2x = t 2dx = dt.

I.F. = e-∫ t dt = e-ln| (t/2)| = e-ln| x| = (1)/(| x|)
Step 2: Solution of LDE
y(I.F.) = ∫ Q(I.F.) dx + C y(1)/( x) = ∫ ² x (1)/( x) dx + C

Let x = t ² x dx = dt.

y(1)/( x) = ∫ (dt)/(t) + C = ln| x| + C y = x(ln| x| + C)
Step 3: Boundary Value

Given y(π/4) = 2:

2 = 1(ln 1 + C) C = 2

Thus, y = x (ln| x| + 2). At x = π/3:

y(π/3) = √(3)(ln√(3) + 2)
Chapter Mix

Class 12 Maths: Differential Equations

More Differential Equations Questions — jee_main_2025_29_jan_evening

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