Core Logic
An aqueous nickel (II) chloride solution contains the green hexaquarickel(II) complex, [Ni(H₂O)₆]²⁺$[\mathrm{Ni}(\mathrm{H}_{2}\mathrm{O})_{6}]^{2+}$. Ethane-1,2-diamine ('en') is a bidentate ligand that binds more strongly than water, shifting the crystal field splitting parameter (Δₒ$\Delta_o$) to higher energies as it replaces water molecules:
[Ni(H₂O)₆]²⁺ (Green)$$[\mathrm{Ni}(\mathrm{H}_{2}\mathrm{O})_{6}]^{2+}\text{ (Green)}$$
- Adding 1 equivalent of 'en' forms a mono-en complex:
[Ni(H₂O)₆]²⁺ + en arrow [Ni(H₂O)₄(en)]²⁺ (Pale Blue) + 2H₂O$$[\mathrm{Ni}(\mathrm{H}_{2}\mathrm{O})_{6}]^{2+} + \mathrm{en} \rightarrow [\mathrm{Ni}(\mathrm{H}_{2}\mathrm{O})_{4}(\mathrm{en})]^{2+}\text{ (Pale Blue)} + 2\mathrm{H}_{2}\mathrm{O}$$
- Adding a 2nd equivalent forms a bis-en complex:
[Ni(H₂O)₄(en)]²⁺ + en arrow [Ni(H₂O)₂(en)₂]²⁺ (Blue / Purple) + 2H₂O$$[\mathrm{Ni}(\mathrm{H}_{2}\mathrm{O})_{4}(\mathrm{en})]^{2+} + \mathrm{en} \rightarrow [\mathrm{Ni}(\mathrm{H}_{2}\mathrm{O})_{2}(\mathrm{en})_{2}]^{2+}\text{ (Blue / Purple)} + 2\mathrm{H}_{2}\mathrm{O}$$
- Adding a 3rd equivalent forms the tris-en complex:
[Ni(H₂O)₂(en)₂]²⁺ + en arrow [Ni(en)₃]²⁺ (Violet) + 2H₂O$$[\mathrm{Ni}(\mathrm{H}_{2}\mathrm{O})_{2}(\mathrm{en})_{2}]^{2+} + \mathrm{en} \rightarrow [\mathrm{Ni}(\mathrm{en})_{3}]^{2+}\text{ (Violet)} + 2\mathrm{H}_{2}\mathrm{O}$$
This progressive ligand replacement shifts the absorption spectrum, changing the solution's visible color from Green arrow$\rightarrow$ Pale Blue arrow$\rightarrow$ Blue arrow$\rightarrow$ Violet.
Pattern Recognition
Replacing weak-field ligands (like H₂O$\mathrm{H}_2\mathrm{O}$) with stronger bidentate chelating ligands (like 'en') increases crystal field splitting. For Ni²⁺$\mathrm{Ni}^{2+}$, this ligand substitution always follows the specific chromatic progression: Green arrow$\rightarrow$ Pale Blue arrow$\rightarrow$ Blue arrow$\rightarrow$ Violet.
Chapter Mix
Class 12 Chemistry: Coordination Compounds