A tiny metallic rectangular sheet has length and breadth of 5 ~mm$5 \mathrm{~mm}$ and 2.5 ~mm$2.5 \mathrm{~mm}$ , respectively. Using a specially designed screw gauge which has pitch of 0.75 ~mm$0.75 \mathrm{~mm}$ and 15 divisions in the circular scale, you are asked to find the area of the sheet. In this measurement, the maximum fractional error will be x100$\frac{\mathrm{x}}{100}$ where x$\mathrm{x}$ is ________.
Numerical Answer Type:
Enter a numerical valueAnswer: 3 to 3+4 marks
Solution & Explanation
Core Logic
First, find the least count of the measurement tool:
Least Count = PitchNumber of circular scale divisions = 0.75 ~mm15 = 0.05 ~mm$$\text{Least Count} = \frac{\text{Pitch}}{\text{Number of circular scale divisions}} = \frac{0.75 \mathrm{~mm}}{15} = 0.05 \mathrm{~mm}$$
Least count calculation tracking diagram for Q21
The area of the rectangular metallic sheet is calculated as:
A = L · W$$\mathrm{A} = \mathrm{L} \cdot \mathrm{W}$$
Expressing the absolute error via fractional configuration parts:
Comparing this to the target format x100$\frac{\mathrm{x}}{100}$ gives:
x = 3$\mathrm{x} = 3$
Pattern Recognition
The absolute measurement uncertainty matches the instrument's least count value directly. Sum up individual fractional errors to compute the total area uncertainty parameter.
The expression given below shows the variation of velocity (v) with time (t), v = At² + (Bt)/(C + t)$v = At^2 + \frac{Bt}{C + t}$ . The dimension of ABC is:
10 divisions on the main scale of a Vernier calliper coincide with 11 divisions on the Vernier scale. If each division on the main scale is of 5 units, the least count of the instrument is:
Watch out for unconventional scale arrangements where VSD > MSD$\text{VSD} > \text{MSD}$. The fundamental difference formula 1 MSD - 1 VSD$1\text{ MSD} - 1\text{ VSD}$ safely determines magnitudes without needing sign corrections.
The radius (r$r$), length (l$l$) and resistance (R$R$) of a metal wire was measured in the laboratory as:
r = (0.35 ± 0.05)~cm$$r = (0.35 \pm 0.05)\mathrm{~cm}$$R = (100 ± 10)~Ω$$R = (100 \pm 10)\mathrm{~\Omega}$$l = (15 ± 0.2)~cm$$l = (15 \pm 0.2)\mathrm{~cm}$$
The percentage error in resistivity of the material of the wire is:
Angular impulse shares the exact same dimensional signature as Planck's constant (h$h$) and angular momentum (L$L$).
Chapter Mix
Class 11 Physics: Units and Measurements
Class 11 Physics: System of Particles and Rotational Motion
Q33jee_main_2024_29_january_eveningError Analysis
A physical quantity Q$Q$ is found to depend on quantities a, b, c$a, b, c$ by the relation Q = (a⁴ b³)/(c²)$Q = \frac{a^4 b^3}{c^2}$. The percentage error in a, b$a, b$ and c$c$ are 3%$3\%$, 4%$4\%$ and 5%$5\%$ respectively. Then, the percentage error in Q$Q$ is:
A.66%$66\%$
B.43%$43\%$
C.34%$34\%$
D.14%$14\%$
Solution
Related Formula
For a quantity Q = (a^x b^y)/(c^z)$Q = \frac{a^x b^y}{c^z}$, the maximum relative error is:
(Δ Q)/(Q) = x (Δ a)/(a) + y (Δ b)/(b) + z (Δ c)/(c)$$\frac{\Delta Q}{Q} = x \frac{\Delta a}{a} + y \frac{\Delta b}{b} + z \frac{\Delta c}{c}$$
Multiplying by 100$100$ gives the percentage error equation:
% error in Q = x(% error in a) + y(% error in b) + z(% error in c)$$\%\text{ error in } Q = x(\%\text{ error in } a) + y(\%\text{ error in } b) + z(\%\text{ error in } c)$$
Error percentages always add up, weighted by their exponents in the mathematical expression, regardless of whether the variable is in the numerator or denominator.
Chapter Mix
Class 11 Physics: Units and Measurements
More Units and Measurements Questions — jee_main_2025_28_jan_morning
Practice past-year questions one chapter at a time. Pick an exam → subject → chapter and get every PYQ for that topic — pulled together from all past papers — with the chapter's key formulas alongside.