JEE Main · Physics ↓ Falling

Units and Measurements appeared 50 times across 3 years — 5.8% of Physics. This question is from Errors in Measurement.

Year 2026 2025 2024 Total
Questions 14 22 14 50

A tiny metallic rectangular sheet has length and breadth of 5 ~mm and 2.5 ~mm , respectively. Using a specially designed screw gauge which has pitch of 0.75 ~mm and 15 divisions in the circular scale, you are asked to find the area of the sheet. In this measurement, the maximum fractional error will be x100 where x is ________.

Numerical Answer Type:
Enter a numerical value Answer: 3 to 3 +4 marks

Solution & Explanation

Core Logic

First, find the least count of the measurement tool:

Least Count = PitchNumber of circular scale divisions = 0.75 ~mm15 = 0.05 ~mm

Least count calculation tracking diagram for Q21
Least count calculation tracking diagram for Q21

The area of the rectangular metallic sheet is calculated as:

A = L · W

Expressing the absolute error via fractional configuration parts:

dAA = dLL + dWW

Substituting the instrument limits (dL = dW = 0.05 ~mm):

dAA = (0.05)/(5) + (0.05)/(2.5) = (1)/(100) + (2)/(100) = (3)/(100)
Step 1: Final Value Match

Comparing this to the target format x100 gives:

x = 3

Pattern Recognition

The absolute measurement uncertainty matches the instrument's least count value directly. Sum up individual fractional errors to compute the total area uncertainty parameter.

Chapter Mix

Class 11 Physics: Units and Measurements

Reference Study Guides

More Units and Measurements Previous-Year Questions — Page 6

Q17 jee_main_2025_03_april_morning Significant Figures in Arithmetic
A person measures mass of 3 different particles as 435.42~g, 226.3~g and 0.125~g. According to the rules for arithmetic operations with significant figures, the additions of the masses of 3 particles will be.
  • A. 661.845~g
  • B. 662~g
  • C. 661.8~g
  • D. 661.84~g

Solution

Related Formula

Significant Figures Rule for Addition/Subtraction: The final result must be rounded off to keep only as many decimal places as there are in the measurement with the least number of decimal places.

Core Logic

Let's look at the decimal places of each measurement:

  • 435.42~g has 2 decimal places.
  • 226.3~g has 1 decimal place.
  • 0.125~g has 3 decimal places.
  • The minimum number of decimal places is 1 decimal place (from 226.3~g).

Step 1: Addition and Rounding

First, perform the standard mathematical addition:

Sum = 435.42 + 226.3 + 0.125 = 661.845~g

Now, round this raw sum off to 1 decimal place:

  • The digit after tenths place is 4 (4 < 5), so we round down.
  • Net rounded sum = 661.8~g.
Pattern Recognition

Bust the common myth: Addition depends on the least number of decimal places, whereas multiplication/division depends on the least number of significant figures. Always distinguish between these two rules during exams!

Chapter Mix

Class 11 Physics: Units and Measurements: Error Analysis and Significant Figures

Q4 jee_main_2025_04_april_evening Dimensions of Physical Quantities
Given below are two statements: Statement (I): The dimensions of Planck's constant and angular momentum are same. Statement (II): In Bohr's model electron revolve around the nucleus only in those orbits for which angular momentum is integral multiple of Planck's constant. In the light of the above statements, choose the most appropriate answer from the options given below:
  • A. Both Statement I and Statement II are correct
  • B. Statement I is incorrect but Statement II is correct
  • C. Statement I is correct but Statement II is incorrect
  • D. Both Statement I and Statement II are incorrect

Solution

Related Formula
E = hf [h] = ([E])/([f]) = ML²T⁻²T⁻¹ = ML²T⁻¹ L = mvr [L] = M · (LT⁻¹) · L = ML²T⁻¹ L = (nh)/(2π)
Core Logic

Statement I: Comparing the dimensional formula of Planck's constant (h) and angular momentum (L), both are identical [ML²T⁻¹]. Hence, Statement I is correct.

Statement II: According to Bohr's second postulate, angular momentum is an integral multiple of (h)/(2π), not an integral multiple of h. Hence, Statement II is incorrect.

Pattern Recognition

Watch out for exact definitions in standard postulates. Bohr's model requires angular momentum to be quantized in units of = (h)/(2π), making statement II a classic trap.

Chapter Mix

Class 11 Physics: Units and Measurements Class 12 Physics: Atoms

Q13 jee_main_2025_04_april_evening Least Count and Vernier Instruments
For the determination of refractive index of glass slab, a travelling microscope is used whose main scale contains 300 equal divisions equals to 15 cm. The vernier scale attached to the microscope has 25 divisions equals to 24 divisions of main scale. The least count (LC) of the travelling microscope is (in cm):
  • A. 0.001
  • B. 0.002
  • C. 0.0005
  • D. 0.0025

Solution

Related Formula
1 MSD = Total LengthTotal Divisions Least Count (LC) = 1 MSD - 1 VSD = 1 MSD · (1 - (24)/(25))
Core Logic

Calculate the value of one main scale division:

1 MSD = 15 cm300 = 0.05 cm

Given that 25 VSD = 24 MSD, we find:

1 VSD = (24)/(25) MSD
Step 1: Compute Least Count
LC = 1 MSD · ((1)/(25)) = 0.05 cm25 = 0.002 cm
Pattern Recognition

Least count calculation is conventionally LC = 1 MSDN where N represents the total count of divisions on the vernier scale whenever (N-1) MSD = N VSD.

Chapter Mix

Class 11 Physics: Units and Measurements

Q20 jee_main_2025_04_april_evening Dimensional Analysis
In an electromagnetic system, a quantity defined as the ratio of electric dipole moment and magnetic dipole moment has dimension of [MpLQTRAS]. The value of P and Q are :
  • A. -1, 0
  • B. -1, 1
  • C. 1, -1
  • D. 0, -1

Solution

Related Formula

Electric Dipole Moment: Pₑ = q · d [Pₑ] = A Magnetic Dipole Moment: Mm = I · A [Mm] = A ²

Core Logic

Take the dimensional ratio:

[(Pₑ)/(Mm)] = LTAL²A = L⁻¹T = M⁰L⁻¹T¹A⁰

Comparing powers with [M^PL^QT^RA^S], we find: P = 0 Q = -1

Pattern Recognition

Dipole units match up with fundamental currents and charge definitions. Notice that current A cancels out completely, leaving a simple geometric spatial ratio.

Chapter Mix

Class 11 Physics: Units and Measurements Class 12 Physics: Moving Charges and Magnetism

Q jee_main_2025_04_april_morning Dimensional Analysis
In an electromagnetic system, the quantity representing the ratio of electric flux and magnetic flux has dimension of MPLQTRAS, where value of 'Q' and 'R' are
  • A. (3, -5)
  • B. (-2, 2)
  • C. (-2, 1)
  • D. (1, -1)

Solution

Related Formula

Ratio formulation:

(φE)/(φM) = (E · A)/(B · A) = (E)/(B)

From Maxwell's electromagnetic wave equations:

E = c · B (E)/(B) = c

where c is the speed of light.

Core Logic

Since the ratio reduces to the dimension of speed (c):

[(φE)/(φM)] = [c] = M⁰ L¹ T⁻¹ A⁰
Step 1: Identify Exponent Values

Matching indices with MPLQTRAS:

  • P = 0
  • Q = 1
  • R = -1
  • S = 0
  • Hence, (Q, R) = (1, -1).

Pattern Recognition

Flux areas cancel out immediately. The ratio (E)/(B) always carries the dimension of velocity (LT⁻¹).

Chapter Mix

Class 11 Physics: Units and Measurements Class 12 Physics: Electromagnetic Waves

More Units and Measurements Questions — jee_main_2025_28_jan_morning

Practice all Units and Measurements previous-year questions →

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JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)