Match List-I with List-II:

List-I	List-II
(A) Angular Impulse	(I) [M^0L^2T^-2]$[M^{0}L^{2}T^{-2}]$
(B) Latent Heat	(II) [M L^2T^-3A^-1]$[M L^{2}T^{-3}A^{-1}]$
(C) Electrical resistivity	(III) [M L^2T^-1]$[M L^{2}T^{-1}]$
(D) Electromotive force	(IV) [M L^3T^-3"A^-2]$[M L^{3}T^{-3"}A^{-2}]$

Choose the correct answer from the options given below:

### Related Formula * **Angular Impulse** = Change in Angular Momentum = tau cdot Delta t = [M L^2 T^-2] cdot [T] = [M L^2 T^-1]$\tau \cdot \Delta t = [M L^2 T^{-2}] \cdot [T] = [M L^2 T^{-1}]$ [cite: 670, 672] * **Latent Heat** (L$L$) = fracQm = frac[M L^2 T^-2][M] = [M^0 L^2 T^-2]$\frac{Q}{m} = \frac{[M L^2 T^{-2}]}{[M]} = [M^0 L^2 T^{-2}]$ * **Electrical resistivity** (\rho) = fracR cdot Al = frac[M L^2 T^-3 A^-2] cdot [L^2][L] = [M L^3 T^-3 A^-2]$\frac{R \cdot A}{l} = \frac{[M L^2 T^{-3} A^{-2}] \cdot [L^2]}{[L]} = [M L^3 T^{-3} A^{-2}]$ * **Electromotive force** (V$V$) = fracWq = frac[M L^2 T^-2][A T] = [M L^2 T^-3 A^-1]$\frac{W}{q} = \frac{[M L^2 T^{-2}]}{[A T]} = [M L^2 T^{-3} A^{-1}]$ ### Core Logic By comparing the formulas derived for each physical quantity with the options given in List-II [cite: 670, 673, 674]: * (A) matches with (III) [cite: 670, 672] * (B) matches with (I) * (C) matches with (IV) * (D) matches with (II) Hence, the correct matching is (A)-(III), (B)-(I), (C)-(IV), (D)-(II). ### Pattern Recognition In match-the-column dimensional analysis questions, identifying even one or two straightforward quantities like Latent Heat (L = Q/m$L = Q/m$) often immediately eliminates three incorrect options, securing a quick correct answer. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Physics: Units and Measurements