Consider the given plots of vapour pressure (VP) vs temperature (T/K) Which amongst the following options is correct graphical representation showing Delta T_mathrmf$\Delta T_{\mathrm{f}}$ , depression in the freezing point of solvent in a solution?

### Related Formula Delta T_f = T_f^0 - T_f$$\Delta T_f = T_f^0 - T_f$$ ### Core Logic Dissolving a non-volatile solute lower the vapor pressure of the solution relative to the pure solvent across all temperature thresholds. The freezing point is defined as the temperature at which the vapor pressure of the liquid phase matches that of its solid phase. Because the solution's vapor pressure curve lies below that of the pure liquid solvent, its intersection with the frozen solvent curve occurs at a lower temperature (T_f < T_f^0$T_f < T_f^0$). This shift creates the characteristic freezing point depression step: Delta T_f = T_f^0 - T_f$\Delta T_f = T_f^0 - T_f$. Plot (3) correctly displays this thermodynamic behavior.

### Pattern Recognition The vapor pressure curve for the solution always runs lower than that of the pure solvent, shifting the freezing intersection to the left. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Solutions