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Aldehydes, Ketones and Carboxylic Acids appeared 46 times across 3 years — 5.4% of Chemistry. This question is from Aldol Condensation and Ozonolysis.

Year 2026 2025 2024 Total
Questions 14 21 11 46

Aman has been asked to synthesise the molecule ring with C—CH3 (x). He thought of preparing the molecule using an aldol condensation reaction. He found a few cyclic alkenes in his laboratory. He thought of performing ozonolysis reaction on alkene to produce a dicarbonyl compound followed by aldol reaction to prepare “x”. Predict the suitable alkene that can lead to the formation of “x”.

Solution & Explanation

Core Logic

Analyzing the retro-synthesis path step-by-step:

  • The objective compound is 1-acetylcyclopentene.
  • Performing reductive ozonolysis (O₃, Zn/H₂O) on 1-methylcyclohexene (Option A) symmetrically breaks the internal endocyclic double bond to form heptane-2,6-dione, a dicarbonyl system.
    Aldol Condensation and Ozonolysis reaction part 1 for Q41
    Aldol Condensation and Ozonolysis reaction part 1 for Q41
  • Adding a base intermediate trigger (OH⁻, Δ) drives an intramolecular aldol condensation: the methyl group carbanion at position 1 attacks the carbon 6 ketone site. This ring-closing event effectively drops water to synthesize the 5-membered cyclopentene core molecule attached to the acetyl unit.
    Aldol Condensation and Ozonolysis reaction part 1 for Q41
    Aldol Condensation and Ozonolysis reaction part 1 for Q41
Pattern Recognition

Counting carbon coordinates is essential. Reductive cleavage transforms a 6-membered ring into an open heptane system, which easily self-condenses into a stable 5-membered ring attached to a methyl ketone side chain.

Chapter Mix

Class 12 Chemistry: Aldehydes, Ketones and Carboxylic Acids

More Aldehydes, Ketones and Carboxylic Acids Previous-Year Questions — Page 9

Q jee_main_2024_30_jan_morning Preparation of Aldehydes
This reduction reaction is known as:
Preparation of Aldehydes diagram for Q62 - JEE Main 2024 Morning
The image shows the catalytic hydrogenation of benzoyl chloride to benzaldehyde in the presence of Pd-BaSO4.
  • A. Rosenmund reduction
  • B. Wolff-Kishner reduction
  • C. Stephen reduction
  • D. Etard reduction

Solution

Related Formula
R-COCl + H₂ Pd/BaSO₄ R-CHO + HCl
Core Logic

The reaction depicts the partial reduction of an acid chloride (benzoyl chloride) to an aldehyde (benzaldehyde) using hydrogen gas in the presence of a poisoned palladium catalyst (Pd supported on BaSO₄).

Preparation of Aldehydes solution diagram for Q62 - JEE Main 2024 Morning
The image shows the catalytic hydrogenation of benzoyl chloride to benzaldehyde in the presence of Pd-BaSO4.
This specific reaction is known as the Rosenmund reduction.

Pattern Recognition

Acid Chloride + H₂, Pd/BaSO₄ arrow Aldehyde is strictly the Rosenmund reduction. The BaSO₄ poisons the catalyst to prevent over-reduction to an alcohol.

Chapter Mix

Class 12 Chemistry: Aldehydes, Ketones and Carboxylic Acids

Q jee_main_2024_30_jan_morning Nomenclature
Structure of 4-Methylpent-2-enal is
  • A. H₂C=C(CH₃)-CH₂-C(=O)H
  • B. CH₃-CH₂-C(CH₃)=CH-C(=O)H
  • C. CH₃-CH₂-CH=C(CH₃)-C(=O)H
  • D. CH₃-CH(CH₃)-CH=CH-C(=O)H

Solution

Core Logic

Decode the IUPAC name: 4-Methylpent-2-enal

  • Word root: 'pent' arrow 5 carbon principal chain.
  • Primary suffix: '2-en' arrow Double bond starting at carbon 2.
  • Secondary suffix: 'al' arrow Aldehyde group (-CHO) at carbon 1.
  • Substituent: '4-Methyl' arrow A methyl group (-CH3) at carbon 4.
Step 1: Drafting the structure

Numbering starts from the aldehyde carbon.

C⁵ - C⁴ - C³ = C² - C¹(=O)H

Attach the methyl at C⁴:

CH₃ - CH(CH₃) - CH = CH - CHO

This matches Option 4.

Chapter Mix

Class 12 Chemistry: Aldehydes, Ketones and Carboxylic Acids Class 11 Chemistry: Organic Chemistry - Some Basic Principles and Techniques

Q jee_main_2024_30_jan_morning Preparation of Aldehydes
In the given reactions identify the reagent A and reagent B.
Preparation of Aldehydes diagram for Q73 - JEE Main 2024 Morning
The image shows the oxidation of toluene to benzaldehyde via two different pathways requiring reagents A and B.
  • A. A-CrO₃, B-CrO₃
  • B. A-CrO₃, B-CrO₂Cl₂
  • C. A-CrO₂Cl₂, B-CrO₂Cl₂
  • D. A-CrO₂Cl₂, B-CrO₃

Solution

Core Logic

Pathway 1 (Upper): Toluene is treated with Reagent 'A' and acetic anhydride (CH₃CO)₂O to form an intermediate (benzylidene diacetate), which on hydrolysis gives benzaldehyde. The reagent used here is Chromic oxide (CrO₃). Thus, A is CrO₃.

Pathway 2 (Lower): Toluene is treated with Reagent 'B' in CS₂ to form a chromium complex intermediate, which on hydrolysis yields benzaldehyde. This is the Etard reaction, and the reagent used is Chromyl chloride (CrO₂Cl₂). Thus, B is CrO₂Cl₂.

Preparation of Aldehydes solution diagram for Q73 - JEE Main 2024 Morning
The image shows the oxidation of toluene to benzaldehyde via two different pathways requiring reagents A and B.

Step 1: Selection

Therefore, A = CrO₃ and B = CrO₂Cl₂.

Pattern Recognition

Etard reaction always uses Chromyl chloride (CrO₂Cl₂). Oxidation of toluene with acetic anhydride uses Chromic acid (CrO₃). Both stop the oxidation at the aldehyde stage via intermediate formation.

Chapter Mix

Class 12 Chemistry: Aldehydes, Ketones and Carboxylic Acids

Q87 jee_main_2024_30_jan_morning Nucleophilic Addition Reactions
The compound formed by the reaction of ethanal with semicarbazide contains ________ number of nitrogen atoms.
Numerical Answer. Answer: 3 to 3

Solution

Related Formula
CH₃-CHO + H₂N-NH-CO-NH₂ arrow CH₃-CH=N-NH-CO-NH₂ + H₂O
Core Logic

Ethanal (CH₃CHO) reacts with semicarbazide (H₂N-NH-CO-NH₂) via nucleophilic addition followed by elimination of water to form a semicarbazone.

Step 1: Product Analysis

The product is Ethanal semicarbazone: CH₃-CH=N-NH-CO-NH₂. Counting the nitrogen atoms in this structure:

  • The imine nitrogen (=N-)
  • The amine nitrogen (-NH-)
  • The amide nitrogen (-NH₂)
  • Total = 3 Nitrogen atoms.

Chapter Mix

Class 12 Chemistry: Aldehydes, Ketones and Carboxylic Acids

Q jee_main_2024_31_jan_evening Preparation of Aldehydes and Ketones
Identify the name reaction.
Preparation of Aldehydes and Ketones diagram for Q73 - JEE Main 2024 Evening
The image shows the conversion of benzene to benzaldehyde using CO, HCl, and Anhydrous AlCl3/CuCl.
  • A. Stephen reaction
  • B. Etard reaction
  • C. Gatterman-koch reaction
  • D. Rosenmund reduction

Solution

Core Logic

The reaction of benzene with carbon monoxide (CO) and hydrogen chloride (HCl) in the presence of anhydrous aluminium chloride (AlCl₃) and cuprous chloride (CuCl) to give benzaldehyde is known as the Gatterman-Koch reaction.

Preparation of Aldehydes and Ketones diagram for Q73 - JEE Main 2024 Evening
The image shows the conversion of benzene to benzaldehyde using CO, HCl, and Anhydrous AlCl3/CuCl.

Pattern Recognition

CO + HCl arrow Formyl chloride intermediate (in situ) with Lewis acid arrow formylation of benzene. This is definitively the Gatterman-Koch formylation.

Chapter Mix

Class 12 Chemistry: Aldehydes, Ketones and Carboxylic Acids

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