Match the LIST-I with LIST-II.

LIST-I (Molecule/ion)	LIST-II (Bond pair : lone pair on the central atom)
(A) mathrmICl_2^-$\mathrm{ICl}_2^-$	(I) 4 : 2$4 : 2$
(B) mathrmH_2mathrmO$\mathrm{H}_2\mathrm{O}$	(II) 4 : 1$4 : 1$
(C) mathrmSO_2$\mathrm{SO}_2$	(III) 2 : 3$2 : 3$
(D) mathrmXeF_4$\mathrm{XeF}_4$	(IV) 2 : 2$2 : 2$

Choose the correct answer from the options given below:

### Core Logic Analyzing the hybridization of the central atom in each species: - NH_3$NH_3$: 3 bp + 1 lp = 4 electron domains rightarrow sp^3$\rightarrow sp^3$ - SO_2$SO_2$: 2 bp + 1 lp = 3 electron domains rightarrow sp^2$\rightarrow sp^2$ - SiO_2$SiO_2$: A giant covalent network where each Si is bonded to 4 oxygens tetrahedrally rightarrow sp^3$\rightarrow sp^3$ - BeCl_2$BeCl_2$: 2 bp + 0 lp = 2 electron domains rightarrow sp$\rightarrow sp$ - CO_2$CO_2$: 2 bp + 0 lp = 2 electron domains rightarrow sp$\rightarrow sp$ - H_2O$H_2O$: 2 bp + 2 lp = 4 electron domains rightarrow sp^3$\rightarrow sp^3$ - CH_4$CH_4$: 4 bp + 0 lp = 4 electron domains rightarrow sp^3$\rightarrow sp^3$ - BF_3$BF_3$: 3 bp + 0 lp = 3 electron domains rightarrow sp^2$\rightarrow sp^2$ Total species with sp^3$sp^3$ hybridization: NH_3, SiO_2, H_2O, CH_4$NH_3, SiO_2, H_2O, CH_4$. Total count = 4. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Chemistry: Chemical Bonding and Molecular Structure