Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason(R). Assertion (A): Magnetic monopoles do not exist. [cite: 138] Reason (R) : Magnetic field lines are continuous and form closed loops. [cite: 138] In the light of the above statements, choose the most appropriate answer from the options given below: [cite: 139]

Solution & Explanation

### Core Logic According to Gauss's Law for Magnetism, the net magnetic flux out of any closed surface is identically zero (oint vecB cdot dvecA = 0). This directly establishes that magnetic poles always occur in equal and opposite pairs (North and South), meaning isolated magnetic monopoles do not exist[cite: 138]. Because every line of magnetic field entering a region must also leave it, these lines are continuous and closed loops[cite: 138]. The non-existence of monopoles is precisely why the field lines form continuous closed paths rather than diverging from or terminating at standalone single pole points[cite: 138]. Both statements are true and (R) provides the definitive causal explanation for (A)[cite: 143, 725]. ### Pattern Recognition Contrast this directly with electrostatics where isolated electric charges do exist, allowing electric field lines to be open lines originating or ending on individual charges. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Physics: Magnetism and Matter

Reference Study Guides

More Magnetism and Matter Previous-Year Questions — Page 2

Q55 jee_main_2024_29_jan_morning Magnetic Dipole
The magnetic potential due to a magnetic dipole at a point on its axis situated at a distance of 20 mathrm~cm from its center is 1.5 times 10^-5 mathrm~T cdot m. The magnetic moment of the dipole is ________ mathrmA cdot m^2. left(text Given: fracmu_04 pi = 10^-7 mathrm~T cdot m cdot A^-1right)$
Numerical Answer. Answer: 6 to 6

Solution

### Related Formula The magnetic potential (V) at an axial location at distance r from the center of a magnetic dipole is given by: V = fracmu_04pi fracMr^2 where M represents the magnetic moment. ### Core Logic Given values: V = 1.5 times 10^-5 mathrm~T cdot m r = 20 mathrm~cm = 0.2 mathrm~m fracmu_04pi = 10^-7 mathrm~T cdot m cdot A^-1 ### Step 1: Set up the Formula Substituting values into the axial expression: 1.5 times 10^-5 = 10^-7 times fracM(0.2)^2 1.5 times 10^-5 = 10^-7 times fracM0.04 ### Step 2: Isolate and Compute M M = frac1.5 times 10^-5 times 0.0410^-7 M = frac0.06 times 10^-510^-7 = 0.06 times 10^2 = 6 mathrm~A cdot m^2 Therefore, the magnetic moment of the dipole is 6 \mathrm{~A \cdot m^2}. ### Pattern Recognition Axial potential fields scale inversely with the square of distance (V \propto \frac{1}{r^2}$), analogous to electrostatic dipole potentials. Ensure the distance is converted directly to meters before squaring. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Physics: Magnetism and Matter

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