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Electromagnetic Waves appeared 31 times across 3 years — 3.6% of Physics. This question is from Intensity of EM Waves.

Year 2026 2025 2024 Total
Questions 10 12 9 31

The unit of 2Iε₀c is: (I = intensity of an electromagnetic wave, c: speed of light) [cite: 10]

Solution & Explanation

Related Formula

I = (1)/(2)ε₀ E₀² c [cite: 670]

Core Logic

Rearranging the equation for intensity I to express the peak electric field amplitude E₀: [cite: 670]

E₀² = (2I)/(ε₀ c)

E₀ = √((2I)/(ε₀ c)) [cite: 670]

Thus, the given quantity is simply the magnitude of the peak electric field E₀[cite: 672]. The standard SI unit of an electric field is Newtons per Coulomb (N· C⁻¹) or Volts per meter (V· m⁻¹)[cite: 673]. Matching with the given structural choices, NC⁻¹ is the correct unit[cite: 31, 669].

Pattern Recognition

Recognize the standard configuration for energy flux density (intensity) I = uavgc[cite: 670]. Identifying that √((2I)/(ε₀ c)) resolves to the electric field dimension directly yields the solution unit NC⁻¹ or V/m[cite: 670, 672, 673].

Chapter Mix

Class 12 Physics: Electromagnetic Waves

Reference Study Guides

More Electromagnetic Waves Previous-Year Questions — Page 7

Q40 jee_main_2024_31_jan_morning Energy Density Of EM Waves
In a plane EM wave, the electric field oscillates sinusoidally at a frequency of 5 × 10¹⁰ ~Hz and an amplitude of 50 ~Vm⁻¹. The total average energy density of the electromagnetic field of the wave is : [Use ε₀ = 8.85 × 10⁻¹² C² / Nm² ]
  • A. 1.106 × 10⁻⁸ Jm⁻³
  • B. 4.425 × 10⁻⁸ ~Jm⁻³
  • C. 2.212 × 10⁻⁸ ~Jm⁻³
  • D. 2.212 × 10⁻¹⁰ ~Jm⁻³

Solution

Related Formula
Utotal average = (1)/(2)ε₀ E₀²
Core Logic

For an electromagnetic wave, the total average energy density is the sum of the average energy density of the electric field and the magnetic field. They are equal, so:

Uavg = UE + UB = 2UE = 2 ( (1)/(4)ε₀ E₀² ) = (1)/(2)ε₀ E₀²

Where E₀ is the amplitude of the electric field.

Step 2: Substitution

Given: E₀ = 50 V/m ε₀ = 8.85 × 10⁻¹² C²/(N· m²)

Uavg = (1)/(2) × (8.85 × 10⁻¹²) × (50)² Uavg = (1)/(2) × 8.85 × 10⁻¹² × 2500 Uavg = 1.10625 × 10⁻⁸ J/m³
Chapter Mix

Class 12 Physics: Electromagnetic Waves

More Electromagnetic Waves Questions — jee_main_2025_07_april_evening

Practice all Electromagnetic Waves previous-year questions →

Rankbit System
JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)