Given below are two statements: Statement (I): On hydrolysis, oligo peptides give rise to fewer number of alpha-amino acids while proteins give rise to a large number of beta-amino acids. Statement (II): Natural proteins are denatured by acids which convert the water soluble form of fibrous proteins to their water insoluble form. In the light of the above statements, choose the most appropriate answer from the options given below:

Statement (I) is incorrect because the complete hydrolysis of both oligopeptides and proteins yields alpha-amino acids, not beta-amino acids. Statement (II) is incorrect because fibrous proteins are inherently water-insoluble structural materials. Denaturation typically disrupts the tertiary and secondary structures of water-soluble globular proteins, making them insoluble. Since both Statement I and Statement II are false, option (3) is the correct choice. All naturally occurring proteins are polymers of alpha-amino acids, so any statement mentioning beta-amino acids as direct translation products can be confidently ruled out. Fibrous proteins (like keratin or collagen) are structural and always insoluble, unlike globular proteins. Class 12 Chemistry: Biomolecules

Given below are two statements: Statement (I): On hydrolysis, oligo peptides give rise to fewer number of alpha-amino acids while proteins give rise to a large number of beta-amino acids. Statement (I

Statement (I) is incorrect because the complete hydrolysis of both oligopeptides and proteins yields alpha-amino acids, not beta-amino acids. Statement (II) is incorrect because fibrous proteins are inherently water-insoluble structural materials. Denaturation typically disrupts the tertiary and secondary structures of water-soluble globular proteins, making them insoluble. Since both Statement I and Statement II are false, option (3) is the correct choice. All naturally occurring proteins are p

Given below are two statements: Statement (I): On hydrolysis, oligo peptides give rise to fewer number of alpha-amino acids while proteins give rise to a large number of beta-amino acids. Statement (II): Natural proteins are denatured by acids which convert the water soluble form of fibrous proteins to their water insoluble form. In the light of the above statements, choose the most appropriate answer from the options given below:

Statement (I) is incorrect because the complete hydrolysis of both oligopeptides and proteins yields alpha-amino acids, not beta-amino acids. Statement (II) is incorrect because fibrous proteins are inherently water-insoluble structural materials. Denaturation typically disrupts the tertiary and secondary structures of water-soluble globular proteins, making them insoluble. Since both Statement I and Statement II are false, option (3) is the correct choice. All naturally occurring proteins are polymers of alpha-amino acids, so any statement mentioning beta-amino acids as direct translation products can be confidently ruled out. Fibrous proteins (like keratin or collagen) are structural and always insoluble, unlike globular proteins. Class 12 Chemistry: Biomolecules

Given below are two statements: Statement (I): On hydrolysis, oligo peptides give rise to fewer number of alpha-amino acids while proteins give rise to a large number of beta-amino acids. Statement (I

Statement (I) is incorrect because the complete hydrolysis of both oligopeptides and proteins yields alpha-amino acids, not beta-amino acids. Statement (II) is incorrect because fibrous proteins are inherently water-insoluble structural materials. Denaturation typically disrupts the tertiary and secondary structures of water-soluble globular proteins, making them insoluble. Since both Statement I and Statement II are false, option (3) is the correct choice. All naturally occurring proteins are p

Given below are two statements: Statement (I): On hydrolysis, oligo peptides give rise to fewer number of alpha-amino…

Year	2026	2025	2024	Total
Questions	9	18	8	35

Q jee_main_2025_02_april_morning Molar Mass Calculations

0.1~mol

of the following given antiviral compound (P) will weigh

\times 10⁻¹~g

Antiviral nucleoside structural layout diagram for Q48 — The diagram displays the full multi-cyclic skeletal structure of an antiviral nucleoside molecule featuring explicit iodine and fluorine atomic positions.

(Given : molar mass in

g \cdot mol⁻¹

H: 1, C: 12, N: 14, O: 16, F: 19, I: 127)

Numerical Answer. Answer: 372 to 372

Solution

Related Formula

Standard molecular weight calculation formula system:

Molar Mass = Σ (Atom Count \times Atomic Weight)

Mass = Moles \times Molar Mass

Core Logic

Let's tabulate and sum up the constituent atoms based on the verified structural formula layout :

Counting positions meticulously yields a molecular identity formula of $C₉H₁₀FIN₂O₄$ $\mathrm{C_9H_{10}FIN_2O_4}$.
Calculating the total molar mass:

Mass = (9 \times 12) + (10 \times 1) + 19 + 127 + (2 \times 14) + (4 \times 16)

Mass = 108 + 10 + 19 + 127 + 28 + 64 = 372~g/mol

Detailed skeletal atomic breakdown calculation diagram for Q48 — The diagram displays the full multi-cyclic skeletal structure of an antiviral nucleoside molecule featuring explicit iodine and fluorine atomic positions.

Step 1: Final Mass Scaling

Find the mass of $0.1~mol$ $0.1\mathrm{~mol}$ of the sample:

Weight = 0.1 \times 372 = 37.2~g = 372 \times 10⁻¹~g

Hence, the integer value for the blank box is 372.

Pattern Recognition

When counting atoms in nucleoside structures, remember that each vertex in the ribose sugar ring represents a fully saturated carbon component unless double bonds or heteroatoms are explicitly drawn.

Chapter Mix

Class 12 Chemistry: Biomolecules Class 11 Chemistry: Some Basic Concepts of Chemistry

Q37 jee_main_2025_02_april_morning Amino Acids Properties

Identify the correct statement among the following:

A. $(1) All naturally occurring amino acids except glycine contain one chiral centre.$
B. $(2) All naturally occurring amino acids are optically active.$
C. $(3) Glutamic acid is the only amino acid that contains a -COOH group at the side chain.$
D. $(4) Amino acid, cysteine easily undergo dimerization due to the presence of free SH group.$

Solution

Related Formula

Dimerization of thiol pairs yields a disulfide linkage via an oxidation mechanism:

2R-SH [-H₂] R-S-S-R

Core Logic

Let's review each choice item factually layout-by-row:

Option 1 is inaccurate: Isoleucine and threonine contain two distinct chiral centers.
Option 2 is inaccurate: Glycine lacks a asymmetric center, rendering it optically inactive.
Option 3 is inaccurate: Aspartic acid similarly contains a carboxylic acid functional group along its side chain.
Option 4 is correct: Cysteine contains a highly active free functional $-SH$ $-\mathrm{SH}$ group that easily dimerizes to form Cystine through a disulfide loop matrix.

Pattern Recognition

Disulfide bridges formed by cysteine play a crucial role in maintaining the tertiary and quaternary structural configurations of complex protein folds.

Chapter Mix

Class 12 Chemistry: Biomolecules

Q28 jee_main_2025_03_april_evening Vitamins Classification

Fat soluble vitamins are: A. Vitamin

B₁

B. Vitamin

C

C. Vitamin

E

D. Vitamin

B₁₂

E. Vitamin

K

Choose the correct answer from the options given below :

A. C & D Only
B. A & B Only
C. B & C Only
D. C & E Only

Solution

Related Formula

Vitamins are classified into two categories based on solubility:

Water-soluble: Vitamin B-complex and Vitamin C.
Fat-soluble: Vitamins A, D, E, and K.

Core Logic

Categorize each given vitamin:

Vitamin $B₁$ $\mathrm{B}_1$ (Thiamine) $arrow$ $\rightarrow$ Water-soluble
Vitamin $C$ $\mathrm{C}$ (Ascorbic acid) $arrow$ $\rightarrow$ Water-soluble
Vitamin $E$ $\mathrm{E}$ (Tocopherol) $arrow$ $\rightarrow$ Fat-soluble
Vitamin $B₁₂$ $\mathrm{B}_{12}$ (Cobalamin) $arrow$ $\rightarrow$ Water-soluble
Vitamin $K$ $\mathrm{K}$ (Phylloquinone) $arrow$ $\rightarrow$ Fat-soluble

Step 1: Select correct options

Only C (Vitamin $E$ $\mathrm{E}$) and E (Vitamin $K$ $\mathrm{K}$) are fat-soluble. Thus, the correct option is (4).

Pattern Recognition

Use the mnemonic 'ADEK' to remember the fat-soluble vitamins. All other vitamins (mainly B-complex and C) are water-soluble.

Chapter Mix

Class 12 Chemistry: Biomolecules

Q jee_main_2025_07_april_morning Hormones Structure

Thyroxine, the hormone has the structure given below:

Chemical skeletal structure of thyroxine hormone for Q47 — The structural formula of Thyroxine shows four iodine atoms attached to the aromatic benzene rings.

The percentage of iodine in thyroxine is ______ %. (nearest integer) (Given molar mass in

g mol⁻¹

of

C: 12

,

H: 1

,

O: 16

,

N: 14

,

I: 127

)

Numerical Answer. Answer: 65 to 65

Solution

Related Formula

% I = 4 \times MIMThyroxine \times 100

Core Logic

Let's first determine the molecular formula of Thyroxine from its structure shown in below :

Thyroxine molecular structure highlight for Q47 — The structural formula of Thyroxine shows four iodine atoms attached to the aromatic benzene rings.

Formula: $C₁₅H₁₁O₄NI₄$

Now, compute the molecular mass:

Carbon: $15 \times 12 = 180$ $15 \times 12 = 180$
Hydrogen: $11 \times 1 = 11$ $11 \times 1 = 11$
Oxygen: $4 \times 16 = 64$ $4 \times 16 = 64$
Nitrogen: $1 \times 14 = 14$ $1 \times 14 = 14$
Iodine: $4 \times 127 = 508$ $4 \times 127 = 508$

Total Molecular Mass = 180 + 11 + 64 + 14 + 508 = 777 g mol⁻¹

Now, calculate the percentage of Iodine:

% I = (508)/(777) \times 100 \approx 65.38 % \approx 65 %

Hence, the percentage of iodine in thyroxine is $65$ $65$.

Pattern Recognition

Thyroxine molecular mass ( $777$ $777$) is composed mostly of Iodine ( $508$ $508$), making up approximately $508/777 \approx 65%$ $508/777 \approx 65\%$ of its entire mass. Always carefully account for the four phenyl-bound iodines.

Evaluation Rubric / Model Answer

Accurate molecular weight summation leading to $65%$ $65\%$ nearest integer Iodine composition.

Chapter Mix

Class 12 Chemistry: Biomolecules Class 12 Chemistry: Organic Chemistry - Oxygen containing compounds

Q43 jee_main_2025_07_april_morning Hydrolysis of Sucrose

Given below are two statements: Statement I:

D-(+)-glucose + D-(+)-fructose -H₂O sucrose sucrose Hydrolysis D-(+)-glucose + D-(+)-fructose

Statement II: Invert sugar is formed during sucrose hydrolysis. In the light of given statements, choose the correct answer from the options given below:

A. $Both Statement I and Statement II are true.$
B. $Statement I is false but Statement II is true.$
C. $Statement I is true but Statement II is false.$
D. $Both Statement I and Statement II are false.$

Solution

Core Logic

Statement I: Sucrose is formed by condensation of $D-(+)-glucose$ $\text{D-(+)-glucose}$ and $D-(-)-fructose$ $\text{D-(-)-fructose}$ (levorotatory fructose, not dextrorotatory as claimed). Hydrolysis of sucrose yields $D-(+)-glucose$ $\text{D-(+)-glucose}$ and $D-(-)-fructose$ $\text{D-(-)-fructose}$. Thus, Statement I is false.

Statement II: Hydrolysis of dextrorotatory sucrose ( $+66.5°$ $+66.5^{\circ}$) yields a mixture of dextrorotatory glucose ( $+52.5°$ $+52.5^{\circ}$) and highly levorotatory fructose ( $-92.4°$ $-92.4^{\circ}$). Because the overall specific rotation of the mixture becomes levorotatory ( $-39.9°$ $-39.9^{\circ}$), the hydrolyzed mixture is called invert sugar. Thus, Statement II is true.

Pattern Recognition

Natural fructose is always levorotatory, $D-(-)-fructose$ $\text{D-(-)-fructose}$. Dextrorotatory fructose mentioned in Statement I is an immediate giveaway that the statement is false.

Chapter Mix

Class 12 Chemistry: Biomolecules

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Related Formula

Core Logic

Step 1: Final Conclusion

Pattern Recognition

Chapter Mix

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