When an object is placed 40mathrm~cm away from a spherical mirror an image of magnification frac12 is produced. To obtain an image with magnification of frac13, the object is to be moved:

Solution & Explanation

### Related Formula Magnification formula in terms of focal length f and object position u: m = fracff - u ### Core Logic Case 1: u_1 = -40mathrm~cm and m_1 = frac12 (assuming real inverted image structure for typical convergence calculations): frac12 = fracff - (-40) implies f + 40 = 2f implies f = 40mathrm~cm (Taking the magnitude parameter yields focal distance benchmark value). ### Step 1: Calculate New Object Position Case 2: To establish m_2 = frac13: frac13 = frac4040 - u_2 implies 40 - u_2 = 120 implies u_2 = -80mathrm~cm ### Step 2: Determine Distance Shift Initial location: -40mathrm~cm Final location: -80mathrm~cm textShift = |u_2| - |u_1| = 80 - 40 = 40mathrm~cmtext away from the mirror. ### Pattern Recognition To reduce the magnification of a real image formed by a concave mirror, the object must always be translated further out away from the focal center point. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Physics: Ray Optics and Optical Instruments

Reference Study Guides

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Q34 jee_main_2024_31_jan_morning Prism Deviation
The refractive index of a prism with apex angle A is cot(A/2). The angle of minimum deviation is :
  • A. delta_mathrmm = 180^circ - A
  • B. delta_mathrmm = 180^circ - 3A
  • C. delta_mathrmm = 180^circ - 4A
  • D. delta_mathrmm = 180^circ - 2A

Solution

### Related Formula mu = fracsinleft(fracA + delta_m2right)sinleft(fracA2right) ### Core Logic Given that the refractive index mu = cotleft(fracA2right). Substituting this into the prism formula: cotleft(fracA2right) = fracsinleft(fracA + delta_m2right)sinleft(fracA2right) fraccosleft(fracA2right)sinleft(fracA2right) = fracsinleft(fracA + delta_m2right)sinleft(fracA2right) Equating the numerators: cosleft(fracA2right) = sinleft(fracA + delta_m2right) We can rewrite cosine in terms of sine: sinleft(fracpi2 - fracA2right) = sinleft(fracA + delta_m2right) ### Step 2: Solve for Deviation Comparing the angles inside the sine functions: fracpi2 - fracA2 = fracA2 + fracdelta_m2 Multiply the entire equation by 2: pi - A = A + delta_m delta_m = pi - 2A Converting radians to degrees: delta_m = 180^circ - 2A ### Pattern Recognition Whenever refractive index mu = cot(A/2), the relation sin(90^circ - A/2) strictly matches the prism sine equation, meaning minimum deviation delta_m is always 180^circ - 2A. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Physics: Ray Optics And Optical Instruments

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