Let the equation x(x + 2)(12 - k) = 2 have equal roots. Then the distance of the point (k, frack2) from the line 3x + 4y + 5 = 0 is

Solution & Explanation

### Related Formula For a quadratic equation ax^2 + bx + c = 0 to have equal roots, its discriminant must be zero: D = b^2 - 4ac = 0 Perpendicular distance of point (x_0, y_0) from line Ax + By + C = 0 is: d = frac|Ax_0 + By_0 + C|sqrtA^2 + B^2 ### Core Logic Let's expand the given equation: (x^2 + 2x)(12 - k) = 2 Let lambda = 12-k. The quadratic equation is: lambda x^2 + 2lambda x - 2 = 0 quad (lambda neq 0) ### Step 1: Finding k Set the discriminant to zero: D = (2lambda)^2 - 4(lambda)(-2) = 0 4lambda^2 + 8lambda = 0 implies 4lambda(lambda + 2) = 0 Since lambda neq 0 (otherwise it is not quadratic and has no roots): lambda = -2 Thus: 12 - k = -2 implies k = 14 ### Step 2: Calculating perpendicular distance The point of interest is: (k, frack2) = (14, 7) Distance from the line 3x + 4y + 5 = 0: d = frac|3(14) + 4(7) + 5|sqrt3^2 + 4^2 = frac|42 + 28 + 5|5 = frac755 = 15 ### Pattern Recognition In quadratic equation analysis, substitution of variable coefficients with parameter lambda keeps calculations clean and helps identify constraints such as lambda neq 0 at early stages. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Mathematics: Quadratic Equations Class 10 Mathematics: Coordinate Geometry

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Q20 jee_main_2024_31_jan_morning Sign of Quadratic Expressions
Let S be the set of positive integral values of a for which fracax^2 + 2(a + 1)x + 9a + 4x^2 - 8x + 32 < 0, forall x in mathbbR. Then, the number of elements in S is:
  • A. 1
  • B. 0
  • C. infty
  • D. 3

Solution

### Core Logic For the denominator x^2 - 8x + 32, D = 64 - 128 < 0 and a = 1 > 0. Thus, x^2 - 8x + 32 > 0 forall x in mathbbR. ### Step 1: Constraint on Numerator Since the denominator is always positive, the numerator must be strictly negative for all x in mathbbR. ax^2 + 2(a + 1)x + 9a + 4 < 0 quad forall x in mathbbR This requires a < 0 and D < 0. ### Step 2: Conclusion Since a must be strictly less than 0, there are no *positive* integral values of a that satisfy the condition. Hence, S is an empty set. Number of elements is 0. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Maths: Quadratic Equations

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