A steel wire of length 2~m$2\mathrm{~m}$ and Young's modulus 2.0× 10¹¹~N/m²$2.0\times 10^{11}\mathrm{~N/m}^2$ is stretched by a force. If Poisson's ratio and transverse strain for the wire are 0.2 and 10⁻³$10^{-3}$ respectively, then the elastic potential energy density of the wire is [value] × 10⁵$\text{[value]} \times 10^{5}$ (in SI units)

Related Formula

Core Logic

The change in pressure Δ P$\Delta P$ is the hydrostatic pressure at depth h$h$.

Step 2: Calculation

Given values: ρ = 10³ kg/m³$\rho = 10^3\mathrm{\,kg/m^3}$ g = 10 m/s²$g = 10\mathrm{\,m/s^2}$ β = 9 × 10⁸ N/m²$\beta = 9 \times 10^8\mathrm{\,N/m^2}$ (Δ V)/(V) = -0.02% = -(0.02)/(100)$\frac{\Delta V}{V} = -0.02\% = -\frac{0.02}{100}$

Substitute into the equation:

Chapter Mix

Class 11 Physics: Mechanical Properties Of Solids Class 11 Physics: Mechanical Properties Of Fluids