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Thermodynamics appeared 36 times across 3 years — 4.2% of Physics. This question is from Isothermal and Adiabatic Processes.

Year 2026 2025 2024 Total
Questions 11 19 6 36

Choose the correct statement for processes A & B shown in figure.
Isothermal and Adiabatic Processes diagram for Q36 - JEE Main 2024 Evening
A Pressure vs Volume (P-V) graph showing two expansion curves starting from the same initial state. Curve B is steeper than Curve A.

Solution & Explanation

Related Formula
Isothermal: PV = constant Adiabatic: PVγ = constant Adiabatic T-P relation: Tγ P1-γ = constant TγPγ - 1 = constant
Core Logic

In a P-V diagram starting from the same initial state and undergoing expansion, the adiabatic curve is steeper than the isothermal curve. Looking at the graph, Curve (B) is steeper, so it represents an adiabatic process. Curve (A) is less steep, so it represents an isothermal process.

Step 1: Check Options

Process A (Isothermal): PV = k or T = k. Process B (Adiabatic): PVγ = k. Option (1) states: PVγ = k for B and PV = k for A. This is entirely correct.

Note: For an adiabatic process, Tγ P1-γ = k, which can be written as TγPγ-1 = k. Option (3) proposes Pγ-1Tγ = k for B, which is mathematically equivalent, but Option (1) is the standard and most direct NTA choice.

Pattern Recognition

Slope of isothermal = -P/V. Slope of adiabatic = -γ P/V. Since γ > 1, adiabatic is always steeper. In expansions, adiabatic lies below isothermal.

Chapter Mix

Class 11 Physics: Thermodynamics

More Thermodynamics Previous-Year Questions — Page 8

Q jee_main_2024_31_jan_morning Isobaric Process
The given figure represents two isobaric processes for the same mass of an ideal gas, then
Isobaric Process diagram for Q38 - JEE Main 2024 Morning
A Volume vs Temperature (V-T) graph showing two straight lines starting from the origin representing distinct constant pressures P1 and P2.
  • A. P₂≥ P₁
  • B. P₂ > P₁
  • C. P₁ = P₂
  • D. P₁ > P₂

Solution

Related Formula

PV = nRT

Core Logic

From the Ideal Gas Law:

V = ((nR)/(P)) T

In a V-T graph, the equation of the line represents y = mx, where the slope m is:

Slope = (nR)/(P) Slope ∝ (1)/(P)

Thus, a higher slope corresponds to a lower pressure.

Step 2: Compare Slopes

From the given figure, the slope of line 2 is greater than the slope of line 1:

(Slope)₂ > (Slope)₁

Therefore, inversely: P₂ < P₁ or P₁ > P₂.

Pattern Recognition

In V-T graphs, steeper lines mean lower Pressure. In P-T graphs, steeper lines mean lower Volume. It's an inverse inverse slope relationship.

Chapter Mix

Class 11 Physics: Thermodynamics

More Thermodynamics Questions — jee_main_2024_30_january_evening

Practice all Thermodynamics previous-year questions →

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