Identify product A and product B :

### Core Logic The substrate is cyclohexene, which can undergo two distinct types of reactions with chlorine (Cl_2$Cl_2$) depending on the reaction conditions. **Reaction 1: Condition hv$hv$ (Product A)** In the presence of light (hnu$h\nu$) or high temperature, halogens undergo homolytic cleavage to generate free radicals. This triggers allylic substitution (a free radical substitution mechanism). The allylic position is targeted because the resulting allylic free radical is resonance stabilized. Thus, substitution occurs at the carbon adjacent to the double bond, yielding 3-chlorocyclohexene as Product A. **Reaction 2: Condition CCl_4$CCl_4$ (Product B)** In the presence of a non-polar solvent like CCl_4$CCl_4$ and without light/heat, Cl_2$Cl_2$ undergoes an electrophilic addition reaction across the carbon-carbon double bond. A cyclic chloronium ion intermediate is formed, leading to anti-addition of two chlorine atoms. This yields 1,2-dichlorocyclohexane as Product B. ### Step 1: Structures of A and B

Product A preserves the double bond and substitutes a Cl at the allylic position. Product B loses the double bond and adds two Cl atoms adjacently. ### Pattern Recognition X_2$X_2$ + light (hnu$h\nu$) = Free radical Allylic Substitution. X_2$X_2$ + dark/solvent (CCl_4$CCl_4$) = Electrophilic Addition across double bond. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Chemistry: Hydrocarbons Class 12 Chemistry: Haloalkanes and Haloarenes