Core Logic
Evaluate dimensions step-by-step:
- Planck's constant (h$h$):
E = h u [h] = ([E])/([ u]) = ML²T⁻²T⁻¹ = ML²T⁻¹$$E = h
u \implies [h] = \frac{[E]}{[
u]} = \frac{\text{ML}^2\text{T}^{-2}}{\text{T}^{-1}} = \text{ML}^2\text{T}^{-1}$$
- Angular momentum (L$L$):
L = mvr [L] = M · LT⁻¹ · L = ML²T⁻¹$$L = mvr \implies [L] = \text{M} \cdot \text{LT}^{-1} \cdot \text{L} = \text{ML}^2\text{T}^{-1}$$
Since [h] = [L]$[h] = [L]$, Statement I is true.
P = mv [P] = MLT⁻¹$$P = mv \implies [P] = \text{MLT}^{-1}$$
- Moment of force (Torque τ$\tau$):
τ = F r [τ] = MLT⁻² · L = ML²T⁻²$$\tau = F r \implies [\tau] = \text{MLT}^{-2} \cdot \text{L} = \text{ML}^2\text{T}^{-2}$$
Since [P] ≠ [τ]$[P] \neq [\tau]$, Statement II is false.
Pattern Recognition
Planck's constant can always be paired with angular momentum units (Joule-seconds), while moment of force matches work/energy footprints, not translational momentum.
Chapter Mix
Class 11 Physics: Units and Measurements