Rankbit System
JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)

If (a, b) be the orthocentre of the triangle whose vertices are (1, 2), (2, 3) and (3, 1), and I_1=int_a^bx~sin(4x-x^2)dx, I_2=int_a^bsin(4x-x^2)dx, then 36fracI_1I_2 is equal to:

Solution & Explanation

### Related Formula int_a^b f(x) dx = int_a^b f(a+b-x) dx quad text(King's Rule) ### Core Logic First, find the orthocentre (a,b) of Delta ABC with vertices A(1, 2), B(2, 3), and C(3, 1). Slope of AB = frac3-22-1 = 1. The altitude from C onto AB must be perpendicular to AB, so its slope is -1. Equation of altitude from C(3,1): y - 1 = -1(x - 3) Rightarrow x + y = 4 The orthocentre (a, b) lies on all altitudes, including this one. Thus, it satisfies a + b = 4. ### Step 1: Applying Definite Integral Properties Given I_1 = int_a^b x sin(4x-x^2) dx, let's rewrite the argument of sine: 4x - x^2 = x(4-x) Apply King's Rule replacing x with (a+b-x). Since we proved a+b = 4, substitute x with (4-x): I_1 = int_a^b (4-x) sin((4-x)(4 - (4-x))) dx I_1 = int_a^b (4-x) sin((4-x)x) dx I_1 = int_a^b (4-x) sin(4x-x^2) dx ### Step 2: Evaluating the Integral Ratio Expand the newly formed integral: I_1 = 4 int_a^b sin(4x-x^2) dx - int_a^b x sin(4x-x^2) dx Notice that the second term is I_1 and the first integral is I_2: I_1 = 4I_2 - I_1 Rightarrow 2I_1 = 4I_2 Rightarrow fracI_1I_2 = 2 ### Step 3: Final Output Evaluation We need the value of 36 fracI_1I_2: 36 times 2 = 72 ### Pattern Recognition Whenever you see int_a^b x cdot f(x(a+b-x)) dx, immediately apply King's Rule to factor out x. You rarely need the individual values of the integration bounds, only their sum. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Maths: Straight Lines Class 12 Maths: Definite Integration

Reference Study Guides

More Definite Integration Previous-Year Questions — Page 4

Q9 jee_main_2024_27_jan_morning Integration of Irrational Functions
If int_0^1frac1sqrt3+x+sqrt1+xdx=a+bsqrt2+csqrt3, where a, b, c are rational numbers, then 2a+3b-4c is equal to:
  • A. 4
  • B. 10
  • C. 7
  • D. 8

Solution

### Related Formula int x^n dx = fracx^n+1n+1 ### Core Logic To evaluate integrals with sum of square roots in the denominator, multiply and divide by the conjugate to rationalize it. I = int_0^1fracsqrt3+x-sqrt1+x(sqrt3+x+sqrt1+x)(sqrt3+x-sqrt1+x)dx I = int_0^1fracsqrt3+x-sqrt1+x(3+x) - (1+x)dx I = frac12 int_0^1 (sqrt3+x - sqrt1+x) dx ### Step 1: Integration and Bounds Setup Integrate the resulting expression: I = frac12 left[ frac(3+x)^3/23/2 - frac(1+x)^3/23/2 right]_0^1 I = frac12 cdot frac23 left[ (3+x)^3/2 - (1+x)^3/2 right]_0^1 I = frac13 left[ ((4)^3/2 - (2)^3/2) - ((3)^3/2 - (1)^3/2) right] ### Step 2: Term Simplification Evaluate the boundary powers: 4^3/2 = 8 2^3/2 = 2sqrt2 3^3/2 = 3sqrt3 1^3/2 = 1 Substitute back into the expression: I = frac13 [ 8 - 2sqrt2 - 3sqrt3 + 1 ] = frac13 [ 9 - 2sqrt2 - 3sqrt3 ] I = 3 - frac23sqrt2 - sqrt3 ### Step 3: Finding Co-efficients Comparing with a+bsqrt2+csqrt3 yields: a = 3, b = -frac23, c = -1 Compute 2a+3b-4c: 2(3) + 3left(-frac23right) - 4(-1) 6 - 2 + 4 = 8 ### Pattern Recognition Whenever you see a sum of square roots in the denominator of an integrand, the immediate algorithmic next step is rationalization. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Maths: Definite Integration

More Definite Integration Questions — jee_main_2024_27_jan_morning

Practice all Definite Integration previous-year questions →

YOUR FIRST PREP STEP STARTS HERE

We Map Every Repeating Question in Competitive Exams.

Say goodbye to generic mock test fatigue. RankBit uses smart analysis to group past exam questions into their foundational Repeating Question Types. Find chapter weightage, track repeating questions, and score higher with targeted practice.

Select Your Target Exam

Choose an exam track below to find formulas per chapter and patterns.

Syncing Exam Intelligence

Mapping formulas and patterns across all tracks…

PATH A — FULL LENGTH PRACTICE

Full Mock Test Hub

Simulate real NTA exam conditions with fully tracked mocks. Time yourself against past papers.

Under Development
PATH B — TARGETED PRACTICE

Topic-wise Practice Hub

Practice past-year questions one chapter at a time. Pick an exam → subject → chapter and get every PYQ for that topic — pulled together from all past papers — with the chapter's key formulas alongside.

Loading Questions... Browse Topics
Latest from the Blog
View all →

Loading articles...