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Differential Equations appeared 46 times across 3 years — 5.3% of Mathematics. This question is from Linear Differential Equations.

Year 2026 2025 2024 Total
Questions 13 17 16 46

If x=x(t) is the solution of the differential equation (t+1)dx=(2x+(t+1)⁴) dt, x(0)=2, then, x(1) equals

Numerical Answer Type:
Enter a numerical value Answer: 14 to 14 +4 marks

Solution & Explanation

Related Formula

A first-order linear differential equation in standard form (dx)/(dt) + P(t)x = Q(t) is solved using the Integrating Factor:

I.F. = e∫ P(t) dt
Core Logic

Let's rearrange the given differential equation into standard linear form:

(t+1)dx = (2x + (t+1)⁴)dt (dx)/(dt) = (2x + (t+1)⁴)/(t+1) (dx)/(dt) - (2)/(t+1)x = (t+1)³
Step 1: Compute Integrating Factor and General Solution

Here, P(t) = -(2)/(t+1) and Q(t) = (t+1)³.

I.F. = e∫ -(2)/(t+1) dt = e-2ln(t+1) = (1)/((t+1)²)

The general solution is given by:

x · I.F. = ∫ Q(t) · I.F. dt + C (x)/((t+1)²) = ∫ (t+1)³ · (1)/((t+1)²) dt + C (x)/((t+1)²) = ∫ (t+1) dt + C = ((t+1)²)/(2) + C
Step 2: Apply Boundary Condition

Given the initial condition x(0) = 2:

(2)/((0+1)²) = ((0+1)²)/(2) + C 2 = (1)/(2) + C C = (3)/(2)

Hence, the specific solution curve is:

(x)/((t+1)²) = ((t+1)²)/(2) + (3)/(2) x(t) = ((t+1)⁴)/(2) + (3)/(2)(t+1)²
Step 3: Evaluate at t = 1

Substituting t = 1:

x(1) = ((1+1)⁴)/(2) + (3)/(2)(1+1)² = (16)/(2) + (3)/(2)(4) = 8 + 6 = 14
Pattern Recognition

Sees: Linear form hidden under differential grouping coefficients. Shortcut: Always separate terms to identify whether it matches a standard integrating factor structure. Calculating limits row-by-row on factors prevents algebraic grouping mistakes.

Chapter Mix

Class 12 Mathematics: Differential Equations

Reference Study Guides

More Differential Equations Previous-Year Questions — Page 10

Q11 jee_main_2024_31_jan_morning Linear Differential Equations
Let y = y(x) be the solution of the differential equation (dy)/(dx) = (( x) + y)/( x( x - x x)), x in (0, (π)/(2)) satisfying the condition y((π)/(4)) = 2. Then, y((π)/(3)) is
  • A. √(3)(2 + ₑ√(3))
  • B. √(3)2(2 + ₑ 3)
  • C. √(3)(1 + 2 ₑ 3)
  • D. √(3)(2 + ₑ 3)

Solution

Core Logic
(dy)/(dx) = (( x)/( x) + y)/( x ((1)/( x) - ( ² x)/( x))) = ( x + y x)/( x (1 - ² x)) (dy)/(dx) = ( x + y x)/( x ² x) = ² x + (2y)/( 2x) (dy)/(dx) - 2 (2x)y = ² x
Step 1: Integrating Factor

This is an LDE of form (dy)/(dx) + Py = Q.

I.F. = e∫ -2 (2x) dx

Let 2x = t 2dx = dt.

I.F. = e-∫ t dt = e-ln| (t/2)| = e-ln| x| = (1)/(| x|)
Step 2: Solution of LDE
y(I.F.) = ∫ Q(I.F.) dx + C y(1)/( x) = ∫ ² x (1)/( x) dx + C

Let x = t ² x dx = dt.

y(1)/( x) = ∫ (dt)/(t) + C = ln| x| + C y = x(ln| x| + C)
Step 3: Boundary Value

Given y(π/4) = 2:

2 = 1(ln 1 + C) C = 2

Thus, y = x (ln| x| + 2). At x = π/3:

y(π/3) = √(3)(ln√(3) + 2)
Chapter Mix

Class 12 Maths: Differential Equations

More Differential Equations Questions — jee_main_2024_01_february_morning

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