Heart of Algebra Previous Year Questions — SAT Math

17 past-year Heart of Algebra questions from SAT (Math) — page 2.

Q3032 (2023)

The following graphs represent a system of linear equations. The lines shown are parallel. How many solutions will this system of equations have? {{IMG1}}
  1. No solution
  2. One solution
  3. Infinite solutions
  4. Because we are not given the equations of the lines, it is impossible to know.
### Related Formula Parallel lines have the same slope ($m_1 = m_2$) but different y-intercepts ($b_1 \neq b_2$). ### Core Logic Parallel lines never cross or intersect at any point in the plane. Since the solution of a system is defined as the set of all intersection points, parallel lines yield zero intersection points. ### Step 1: Conclusion Therefore, the system has no solution. ### Pattern Recognition Parallel lines $\rightarrow$ zero intersections $\rightarrow$ no solution. ### Evaluation Rubric / Model Answer null ### Chapter Mix SAT Math: Heart of Algebra

Q3033 (2023)

Which of the following graphs demonstrates a system of linear equations with no solution? i. {{IMG1}} ii. {{IMG2}} iii. {{IMG3}} iv. {{IMG4}}
  1. i & ii
  2. ii & iv
  3. iii & iv
  4. ii & iii
### Related Formula A system of linear equations has no solution if and only if the lines are parallel. ### Core Logic Examine each graph for parallel lines: - Graph i shows perpendicular lines (one vertical, one horizontal). - Graph ii shows two horizontal parallel lines. - Graph iii shows two vertical parallel lines. - Graph iv shows intersecting lines. ### Step 1: Conclusion Since graphs ii and iii depict parallel lines, both systems have no solution. Hence, option D is correct. ### Pattern Recognition Identify parallel orientation in multi-graph sets $\rightarrow$ both represent no solution systems. ### Evaluation Rubric / Model Answer null ### Chapter Mix SAT Math: Heart of Algebra

Q3036 (2023)

A man buys $a$ apples and $g$ oranges, each costing 80 cents and 60 cents respectively. If the man buys less than 18 fruits and spends less than $12, which of the following is the correct inequality representing the above information?
  1. $a + g = 18$ $4a + 3g = 60$
  2. $a + g < 18$ $4a + 3g < 60$
  3. $a + g \le 18$ $4a + 3g \le 60$
  4. $a + g \le 18$ $4a + 3g = 60$
### Related Formula $$\text{Total Cost (cents)} = 80a + 60g < 1200$$ since $\$12 = 1200$ cents. ### Core Logic Fruit quantity condition: buys 'less than 18 fruits' $\rightarrow a + g < 18$. Cost condition: spends 'less than $\$12$' $\rightarrow 80a + 60g < 1200$. Simplify the cost inequality by dividing all terms by 20: $$\frac{80a}{20} + \frac{60g}{20} < \frac{1200}{20} \implies 4a + 3g < 60$$ ### Step 1: Conclusion The system of inequalities is $a + g < 18$ and $4a + 3g < 60$ (Option B). ### Pattern Recognition 'Less than' strictly means $<$, not $\leq$. Convert dollars to cents before simplifying. ### Evaluation Rubric / Model Answer null ### Chapter Mix SAT Math: Heart of Algebra

Q5 (2023)

Samantha bought M&Ms from the store. She is told that the amount of sweet M&Ms and the amount of bitter M&Ms is represented by the following system of inequalities, where $s$ is the number of sweet M&Ms and $b$ is the number of bitter M&Ms: $s + b \geq 25$ $5s - 10b < 2$ Which of the following solutions, in the format $(s, b)$ could be a possible solution for the number of M&Ms in Samantha's bag?
  1. $(6, 10)$
  2. $(2, 30)$
  3. $(1, 1)$
  4. $(50, 10)$
### Related Formula For a coordinate pair $(s, b)$ to be a valid solution to a system of inequalities, it must satisfy all given inequalities simultaneously. ### Core Logic Test the ordered pair $(2, 30)$ where $s = 2$ and $b = 30$: First inequality: $$2 + 30 = 32 \geq 25 \quad \text{(True)}$$ Second inequality: $$5(2) - 10(30) = 10 - 300 = -290 < 2 \quad \text{(True)}$$ ### Step 1: Conclusion Since both statements evaluate to true for $(2, 30)$, option B is a valid solution. ### Pattern Recognition System of inequalities question $\rightarrow$ plug and check given options to find which makes both true. ### Evaluation Rubric / Model Answer null ### Chapter Mix SAT Math: Heart of Algebra

Q9 (2023)

If $a + 2b + 3c = 24$ and $3a + 2b + c = 36$, what is the value of $(a + b + c)$?
  1. 8
  2. 12
  3. 15
  4. 60
### Related Formula For symmetric linear systems, adding equations directly often isolates the required expression $(a + b + c)$ without solving for individual variables. ### Core Logic Given equations: $$a + 2b + 3c = 24 \quad \dots (1)$$ $$3a + 2b + c = 36 \quad \dots (2)$$ Add (1) and (2) together: $$(a + 3a) + (2b + 2b) + (3c + c) = 24 + 36$$ $$4a + 4b + 4c = 60$$ ### Step 1: Solve for (a + b + c) Factor out 4: $$4(a + b + c) = 60$$ Divide by 4: $a + b + c = 15$ Thus, the correct answer is C. ### Pattern Recognition Symmetric coefficients $\rightarrow$ add equations directly to avoid tedious multi-variable elimination. ### Evaluation Rubric / Model Answer null ### Chapter Mix SAT Math: Heart of Algebra
Rankbit System
JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)

Select Your Target Exam

Choose an exam track below to find formulas per chapter and patterns.

Syncing Exam Intelligence

Mapping formulas and patterns across all tracks…

PATH A — FULL LENGTH PRACTICE

Full Mock Test Hub

Simulate real NTA exam conditions with fully tracked mocks. Time yourself against past papers.

Now Live Open
PATH B — TARGETED PRACTICE

Topic-wise Practice Hub

Practice past-year questions one chapter at a time. Pick an exam → subject → chapter and get every PYQ for that topic — pulled together from all past papers — with the chapter's key formulas alongside.

Loading Questions... Browse Topics
Latest from the Blog
View all →

Loading articles...