Q22 (2024)
For a travelling harmonic wave
$$\mathrm{y} (x, t) = 2.0 \cos 2 \pi (10 t - 0.0080 x + 0.35)$$
here x and y are in cm and t in s. The phase difference between oscillatory motion of two points separated by a distance of 0.5 m is:
- $8\pi \mathrm{rad}$
- $0.08\pi \mathrm{rad}$
- $0.008\pi \mathrm{rad}$
- $0.8\pi \mathrm{rad}$
### Related Formula
$$\Delta \phi = k \Delta x$$
$$k = 2\pi \times 0.0080 \text{ rad/cm}$$
### Core Logic
$\Delta x = 0.5\text{ m} = 50\text{ cm}$.
$$\Delta \phi = 2\pi \times 8 \times 10^{-3} \times 50 = 800 \pi \times 10^{-3} = 0.8\pi \text{ rad}$$
### Pattern Recognition
Phase difference is wave number times path length difference.
### Evaluation Rubric / Model Answer
null
### Chapter Mix
Class 11 Physics: Waves
