Q12 (2024)
A galvanometer of resistance $100\Omega$ gives full scale deflection for a current of 1 mA. It is converted into an ammeter of range 0–10 A. The shunt required is:
- $0.01\Omega$
- $0.10\Omega$
- $0.001\Omega$
- $1.0\Omega$
### Related Formula
$$i_{S} r_{S} = i_{G} R_{G}$$
### Core Logic
Given $i_{G} = 1\text{ mA} = 0.001\text{ A}$, $R_G = 100\Omega$, $I = 10\text{ A}$.
$i_{S} = I - i_G \approx 10\text{ A}$.
{{SOL_IMG1}}
$$10 \times r_{s} = 0.001 \times 100 \Rightarrow r_{s} = 0.01\Omega$$
### Pattern Recognition
Shunt resistance calculation for ammeter conversion.
### Evaluation Rubric / Model Answer
null
### Chapter Mix
Class 12 Physics: Moving Charges and Magnetism
