Q39 (2024)
A submarine is designed to withstand an absolute pressure of 100 atm. How deep can it go below the water surface?
(Consider the density of water = 1000 kg m $^{-3}$ , 1 atm = 1 × 10 $^{5}$ Pa and gravitational acceleration g = 10 m / s $^{2}$ )
- 9900 m
- 99 m
- 9000 m
- 990 m
### Related Formula
$$P = P_0 + \rho g h$$
### Core Logic
$$100 \times 10^5 = 10^5 + 10^3 \times 10 \times h$$
$$10^7 = 10^5 + 10^4 h$$
$$10^3 = 10 + h \Rightarrow h = 990 \text{ m}$$
### Pattern Recognition
Absolute pressure calculation including atmospheric pressure baseline.
### Evaluation Rubric / Model Answer
null
### Chapter Mix
Class 11 Physics: Mechanical Properties of Fluids
