Alternating Current Previous Year Questions — NEET Physics

2 past-year Alternating Current questions from NEET (Physics).

Q7 (2024)

An ac circuit contains a resistance of 1 kΩ, a capacitor of 0.1 μF and an inductor of 1 mH connected in series. The resonance frequency of the circuit is approximately.
  1. 10.1 kHz
  2. 20.7 kHz
  3. 15.9 kHz
  4. 13.5 kHz
### Related Formula $$f_{0} = \frac{1}{2\pi\sqrt{LC}}$$ ### Core Logic $$f_{0} = \frac{1}{2\pi\sqrt{1\times 10^{-3} \times 0.1\times 10^{-6}}} = \frac{1}{2\pi\sqrt{10^{-10}}} = \frac{10^{5}}{2\pi} \approx 15.9\text{ kHz}$$ ### Pattern Recognition Direct application of series LCR resonance frequency formula. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Physics: Alternating Current

Q33 (2024)

The peak value of an alternating current is 5 A and frequency is 60 Hz. How long will the current, starting from zero, take to reach the peak value?
  1. $\frac{1}{240} \text{ s}$
  2. $\frac{1}{30} \text{ s}$
  3. $\frac{1}{120} \text{ s}$
  4. $\frac{1}{60} \text{ s}$
### Related Formula $$i = i_{\text{peak}} \sin(\omega t)$$ $$t = \frac{T}{4} = \frac{1}{4f}$$ ### Core Logic Time to reach peak value from zero is one-fourth of the time period $T$. $$t = \frac{1}{4 \times 60} = \frac{1}{240} \text{ s}$$ ### Pattern Recognition Time to reach peak value from zero in AC is T/4. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Physics: Alternating Current
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JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)

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