Structure of Atom Previous Year Questions — NEET Chemistry

2 past-year Structure of Atom questions from NEET (Chemistry).

Q50 (2024)

Match List I with List II: <div style="overflow-x: auto; margin: 1rem 0;"><table style="width: 100%; border-collapse: collapse; text-align: left; font-size: 14px;"><thead><tr><th style="border: 1px solid #888; padding: 8px;">List-I (Quantum Numbers: n, l)</th><th style="border: 1px solid #888; padding: 8px;">List-II (Orbital)</th></tr></thead><tbody><tr><td style="border: 1px solid #888; padding: 8px;">A. n = 2, l = 1</td><td style="border: 1px solid #888; padding: 8px;">(I) 3d</td></tr><tr><td style="border: 1px solid #888; padding: 8px;">B. n = 4, l = 0</td><td style="border: 1px solid #888; padding: 8px;">(II) 2p</td></tr><tr><td style="border: 1px solid #888; padding: 8px;">C. n = 5, l = 3</td><td style="border: 1px solid #888; padding: 8px;">(III) 4s</td></tr><tr><td style="border: 1px solid #888; padding: 8px;">D. n = 3, l = 2</td><td style="border: 1px solid #888; padding: 8px;">(IV) 5f</td></tr></tbody></table></div> Choose the correct answer from the options given below:
  1. (1) A-II, B-III, C-IV, D-I
  2. (2) A-I, B-II, C-III, D-IV
  3. (3) A-IV, B-II, C-III, D-I
  4. (4) A-II, B-III, C-I, D-IV
### Related Formula $$l = 0 \rightarrow s, \quad l = 1 \rightarrow p, \quad l = 2 \rightarrow d, \quad l = 3 \rightarrow f$$ ### Core Logic A: $n=2, l=1 \implies 2p$ (II) B: $n=4, l=0 \implies 4s$ (III) C: $n=5, l=3 \implies 5f$ (IV) D: $n=3, l=2 \implies 3d$ (I) Matches: A-II, B-III, C-IV, D-I. ### Step 1: Conclusion Correct option is (1). ### Pattern Recognition Direct mapping of azimuthal quantum number $l$ to orbital subshell letters. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Chemistry: Structure of Atom

Q59 (2024)

A bulb is rated at 150 watt, converting 8% energy into light. If energy of one photon is $4.42 \times 10^{-19} \text{ J}$, how many photons are emitted by the bulb per second?
  1. (1) $1.35 \times 10^{19}$
  2. (2) $4.06 \times 10^{19}$
  3. (3) $2.71 \times 10^{19}$
  4. (4) $27.2 \times 10^{19}$
### Related Formula $$P_{\text{useful}} = P \times \text{efficiency}$$ $$N = \frac{E_{\text{light}}}{E_{\text{photon}}}$$ ### Core Logic $$E_{\text{total}} = 150 \text{ J/s}$$ $$E_{\text{light}} = 150 \times \frac{8}{100} = 12 \text{ J/s}$$ $$N = \frac{12}{4.42 \times 10^{-19}} = 2.715 \times 10^{19} \text{ photons/s}$$ ### Step 1: Final Selection Number of photons emitted per second is $2.71 \times 10^{19}$. ### Pattern Recognition Always calculate effective power in Joules per second before dividing by single photon energy. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Chemistry: Structure of Atom
Rankbit System
JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)

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