Amines Previous Year Questions — NEET Chemistry

3 past-year Amines questions from NEET (Chemistry).

Q47 (2024)

The major product Z formed in the following sequence of reactions is: $$C_2H_6 \xrightarrow[UV \text{ light}]{Cl_2} X_{\text{(monochlorinated Product)}} \xrightarrow{NH_3} Y \xrightarrow[\text{(ii)} H_2O]{\text{(i)} NaNO_2/HCl} Z$$
  1. (1) $C_2H_5-N=N-OH$
  2. (2) $C_2H_5OH$
  3. (3) $C_2H_5NO_2$
  4. (4) $C_2H_5NH_2$
### Related Formula $$R-NH_2 \xrightarrow{NaNO_2 + HCl} [R-N_2^+ Cl^-] \xrightarrow{H_2O} R-OH + N_2 + HCl$$ ### Core Logic Step 1: Chlorination of ethane gives ethyl chloride ($X = C_2H_5Cl$). Step 2: Reaction with ammonia gives ethylamine ($Y = C_2H_5NH_2$). Step 3: Diazotization of primary aliphatic amine yields unstable diazonium salt which hydrolyzes to ethanol ($Z = C_2H_5OH$). ### Step 1: Final Product Identification Therefore, major product $Z$ is ethanol ($C_2H_5OH$). ### Pattern Recognition Aliphatic primary amine + nitrous acid ($NaNO_2/HCl$) always decomposes to alcohol + $N_2$ gas. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Amines

Q61 (2024)

Select the reagents that reduce nitriles to primary amines. A. (i) $LiAlH_4$; (ii) $H_2O$ B. $Sn + HCl$ C. $H_2 / Ni$ D. $Na(Hg) / C_2H_5OH$ E. $Br_2 / aq. \text{ NaOH}$ Choose the correct answer from the options given below:
  1. (1) A, B and C only
  2. (2) A, C and D only
  3. (3) A, D and E only
  4. (4) B, D and E only
### Related Formula $$R-CN \xrightarrow{\text{Reduction}} R-CH_2-NH_2$$ ### Core Logic A. $LiAlH_4$ reduces nitriles to $R-CH_2-NH_2$. B. $Sn + HCl$ reduces nitriles to aldehydes (Stephen reduction intermediate). C. $H_2/Ni$ catalytically reduces nitriles to $R-CH_2-NH_2$. D. $Na(Hg)/C_2H_5OH$ (Mendius reduction) yields $R-CH_2-NH_2$. E. $Br_2/NaOH$ is Hoffmann bromamide degradation for amides, not nitriles. ### Step 1: Selection Reagents A, C, and D perform reduction of nitriles to primary amines. ### Pattern Recognition $LiAlH_4$, catalytic hydrogenation, and $Na(Hg)/EtOH$ convert $R-CN \rightarrow R-CH_2NH_2$. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Amines

Q89 (2024)

The following two reactions give the same foul smelling product Z: $$C_2H_5Cl \xrightarrow{X} Z$$ $$C_2H_5CONH_2 \xrightarrow{Br_2, NaOH} Y \xrightarrow[\Delta]{CHCl_3 / \text{ethanolic KOH}} Z$$ X and Z, respectively, are:
  1. (1) $X = AgCN; Z = C_2H_5CN$
  2. (2) $X = KCN; Z = C_2H_5CN$
  3. (3) $X = KCN; Z = C_2H_5NC$
  4. (4) $X = AgCN; Z = C_2H_5NC$
### Related Formula $$R-Cl + AgCN \rightarrow R-NC + AgCl$$ $$R-NH_2 + CHCl_3 + 3KOH \rightarrow R-NC + 3KCl + 3H_2O$$ ### Core Logic Reaction 1: Ethyl chloride + $AgCN \rightarrow$ Ethyl isocyanide ($Z = C_2H_5NC$). Reaction 2: Propanamide + $Br_2/NaOH \rightarrow$ Ethylamine ($Y = C_2H_5NH_2$). Carbylamine test on $Y$ produces foul-smelling ethyl isocyanide ($Z = C_2H_5NC$). ### Step 1: Conclusion $X = AgCN$ and $Z = C_2H_5NC$. ### Pattern Recognition Foul-smelling substance = Isocyanide ($R-NC$). Covalent $AgCN$ attacks via nitrogen to yield isocyanide. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Amines
Rankbit System
JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)

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