Q1488 (2024)
Which one of the following will show geometrical isomerism?
- Option (1)
- Option (2)
- Option (3)
- Option (4)
### Related Formula
$$\text{Condition for Geometrical Isomerism: } \text{C}=\text{C} \text{ must have distinct groups attached to each olefinic carbon.}$$
### Core Logic
For a compound containing a carbon-carbon double bond to exhibit geometrical ($cis/trans$) isomerism, neither of the two alkene carbons can have two identical groups attached to it.
Evaluating Option (3), both olefinic carbons are unsymmetrically substituted with two completely different groups, satisfying all geometric requirements for stereoisomerism.
### Step 1: Conclusion
The structural composition of Option (3) enables it to form distinct spatial structures, allowing it to exhibit geometrical isomerism.
### Pattern Recognition
Check both ends of the double bond. If either carbon contains identical groups, geometrical isomerism is structurally impossible.
### Evaluation Rubric / Model Answer
null
### Chapter Mix
Class 11 Chemistry: Isomerism of Organic Compounds
