Q53 (2026)
Consider the elements N, P, O, S, Cl and F. The number of valence electrons present in the elements with most and least metallic character from the above list is respectively.
- $(1)\text{ 7 and 5}$
- $(2)\text{ 5 and 6}$
- $(3)\text{ 5 and 7}$
- $(4)\text{ 6 and 7}$
### Core Logic
Metallic character decreases across a period and increases down a group.
Among N, P, O, S, Cl and F:
Least metallic element = F (Group 17, Period 2), valence electrons = 7.
Most metallic element = P (Group 15, Period 3), valence electrons = 5.
### Step 1: Final Conclusion
The number of valence electrons for most and least metallic elements are 5 and 7 respectively.
### Pattern Recognition
F is the most electronegative (least metallic). P is the lowest and leftmost in this non-metal set (most metallic).
### Evaluation Rubric / Model Answer
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### Chapter Mix
Class 11 Chemistry: Classification of Elements and Periodicity in Properties
