JEE Main · Physics ↓ Falling

Dual Nature of Radiation and Matter appeared 31 times across 3 years — 3.6% of Physics. This question is from Photon Energy.

Year 2026 2025 2024 Total
Questions 7 16 8 31

Number of photons of equal energy emitted per second by a 6 mW laser source operating at 663 nm is ____. (Given: h = 6.63 × 10⁻³⁴ J.s and c = 3 × 10⁸ m/s)

Solution & Explanation

Related Formula
P = n (hc)/(λ)

where: P = Power of the laser n = number of photons emitted per second h = Planck's constant c = speed of light λ = wavelength

Step 1: Extract Given Variables

P = 6 mW = 6 × 10⁻³ J/s λ = 663 nm = 663 × 10⁻⁹ m h = 6.63 × 10⁻³⁴ J.s c = 3 × 10⁸ m/s

Step 2: Substitution and Calculation
6 × 10⁻³ = n × 6.63 × 10⁻³⁴ × 3 × 10⁸663 × 10⁻⁹

Notice that 6.63 / 663 = 10⁻².

6 × 10⁻³ = n × 3 × 10⁻²⁶ × 10⁻²10⁻⁹ 6 × 10⁻³ = n × 3 × 10⁻¹⁹ n = 6 × 10⁻³3 × 10⁻¹⁹ = 2 × 10¹⁶
Pattern Recognition

Always look for complementary numerical values like 663 and 6.63. It guarantees a clean power of 10 extraction.

Chapter Mix

Class 12 Physics: Dual Nature of Radiation and Matter

Reference Study Guides

More Dual Nature of Radiation and Matter Previous-Year Questions — Page 7

Q50 jee_main_2024_31_jan_morning Photoelectric Effect
When a metal surface is illuminated by light of wavelength λ, the stopping potential is 8 V. When the same surface is illuminated by light of wavelength 3λ, stopping potential is 2 V. The threshold wavelength for this surface is:
  • A. 5λ
  • B. 3λ
  • C. 9λ
  • D. 4.5λ

Solution

Related Formula
(hc)/(λ) = φ + Kmax Kmax = eV₀ φ = (hc)/(λ₀)
Core Logic

Using Einstein's Photoelectric equation for the two cases:

Case 1 (Wavelength λ, Stopping Potential 8 V):

(hc)/(λ) = (hc)/(λ₀) + 8e (i)

Case 2 (Wavelength 3λ, Stopping Potential 2 V):

(hc)/(3λ) = (hc)/(λ₀) + 2e (ii)
Step 2: Solving the Equations

Multiply equation (ii) by 4 to eliminate e:

(4hc)/(3λ) = (4hc)/(λ₀) + 8e

Equating this to equation (i):

(hc)/(λ) - (hc)/(λ₀) = (4hc)/(3λ) - (4hc)/(λ₀)

Divide entirely by hc:

(1)/(λ) - (1)/(λ₀) = (4)/(3λ) - (4)/(λ₀) (4)/(λ₀) - (1)/(λ₀) = (4)/(3λ) - (1)/(λ) (3)/(λ₀) = (4 - 3)/(3λ) (3)/(λ₀) = (1)/(3λ) λ₀ = 9λ
Chapter Mix

Class 12 Physics: Dual Nature Of Radiation And Matter

More Dual Nature of Radiation and Matter Questions — jee_main_2026_28_january_evening

Practice all Dual Nature of Radiation and Matter previous-year questions →

Rankbit System
JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)