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Aldehydes, Ketones and Carboxylic Acids appeared 46 times across 3 years — 5.3% of Chemistry. This question is from Preparation of Carboxylic Acids.

Year 2026 2025 2024 Total
Questions 14 21 11 46

Grignard reagent RMgBr(P) reacts with water and forms a gas (Q). One gram of Q occupies 1.4 dm ³ at STP. (P) on reaction with dry ice in dry ether followed by H₃O⁺ forms a compound (Z). 0.1 mole of (Z) will weigh ____ g. (Nearest integer)

Numerical Answer Type:
Enter a numerical value Answer: 6 to 6 +4 marks

Solution & Explanation

Core Logic

Gas (Q) is formed when RMgBr reacts with water. Thus, Q is the alkane RH. We are given that 1.0 gm of Q occupies 1.4 ~dm³ (or 1.4 ~L) at STP. Using molar volume (22.4 ~L at STP for 1 mole): Molar mass of Q = (22.4)/(1.4) × 1 = 16 g/mol. The alkane with molecular weight 16 is Methane (CH₄). So, R must be the methyl group (CH₃-). The Grignard reagent (P) is CH₃MgBr.

Step 1: Reaction with Dry Ice

Reaction of Methylmagnesium bromide with dry ice (CO₂):

CH₃MgBr [(ii) H₃O^+](i) CO₂ (dry ice) CH₃COOH

The final compound (Z) is Acetic Acid (CH₃COOH).

Preparation of Carboxylic Acids diagram for Q75 - JEE Main 2026 Evening
Preparation of Carboxylic Acids diagram for Q75 - JEE Main 2026 Evening

Step 2: Calculate Final Mass

Molar weight of Acetic Acid (CH₃COOH) = 12 + 3(1) + 12 + 16(2) + 1 = 60 g/mol. Weight of 0.1 mole of CH₃COOH = 0.1 × 60 = 6 g.

Pattern Recognition

When evaluating the identity of a Grignard reagent, use STP volume scaling to find the exact molar mass of its alkane derivative. 1.4 × 16 = 22.4 is an extremely common dimensional hook.

Chapter Mix

Class 12 Chemistry: Aldehydes, Ketones and Carboxylic Acids Class 11 Chemistry: Hydrocarbons

Reference Study Guides

More Aldehydes, Ketones and Carboxylic Acids Previous-Year Questions — Page 10

Q jee_main_2024_31_jan_morning Reactions with Grignard Reagent
The product of the following reaction is P.
Reactions with Grignard Reagent diagram for Q84 - JEE Main 2024 Morning
The image shows p-hydroxybenzaldehyde reacting with one equivalent of PhMgBr followed by aqueous ammonium chloride.
The number of hydroxyl groups present in the product P is
Numerical Answer. Answer: 0 to 0

Solution

Core Logic

The given reactant is p-hydroxybenzaldehyde, which contains both a phenolic -OH group (acidic) and an aldehyde group (electrophilic).

When one equivalent of Grignard reagent (PhMgBr) is added, it behaves primarily as a strong base due to the presence of an acidic proton. Acid-base reactions are extremely fast compared to nucleophilic additions.

The acidic phenolic -OH reacts with PhMgBr:

PhMgBr + HO-C₆H₄-CHO arrow Ph-H (Benzene) + BrMg-O-C₆H₄-CHO

Upon workup with aq. NH₄Cl, the phenoxide ion simply regenerates the starting p-hydroxybenzaldehyde. However, the question asks for the number of hydroxyl groups present in the formed product (Benzene).

Reactions with Grignard Reagent diagram for Q84 - JEE Main 2024 Morning
The image shows p-hydroxybenzaldehyde reacting with one equivalent of PhMgBr followed by aqueous ammonium chloride.

The distinct product formed in the reaction is Benzene. Benzene has 0 hydroxyl groups.

Pattern Recognition

Whenever a Grignard reagent encounters a molecule with an acidic hydrogen (alcohol, phenol, amine, alkyne), it will invariably act as a base first. If only 1 equivalent is used, nucleophilic addition to carbonyls will NOT happen.

Chapter Mix

Class 12 Chemistry: Aldehydes, Ketones and Carboxylic Acids Class 12 Chemistry: Alcohols, Phenols and Ethers

More Aldehydes, Ketones and Carboxylic Acids Questions — jee_main_2026_24_january_evening

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