JEE Main · Mathematics → Steady

Statistics appeared 21 times across 3 years — 2.4% of Mathematics. This question is from Mean and Variance.

Year 2026 2025 2024 Total
Questions 7 7 7 21

Let the mean and variance of 8 numbers -10, -7, -1, x, y, 9, 2, 16 be (7)/(2) and (293)/(4), respectively. Then the mean of 4 numbers x, y, x + y + 1, |x - y| is:

Solution & Explanation

Related Formula
μ = (Σ xᵢ)/(N) σ² = (Σ xᵢ²)/(N) - μ²
Core Logic

Calculate x+y using the mean formula:

(-10 - 7 - 1 + x + y + 9 + 2 + 16)/(8) = (7)/(2) (9 + x + y)/(8) = (7)/(2) ⇒ 9 + x + y = 28 ⇒ x + y = 19 (1)
Step 1: Calculate sum of squares using Variance

Using the variance formula:

((-10)² + (-7)² + (-1)² + x² + y² + 9² + 2² + 16²)/(8) - ((7)/(2))² = (293)/(4) (100 + 49 + 1 + x² + y² + 81 + 4 + 256)/(8) - (49)/(4) = (293)/(4) (491 + x² + y²)/(8) = (293)/(4) + (49)/(4) = (342)/(4) = (684)/(8) 491 + x² + y² = 684 ⇒ x² + y² = 193 (2)
Step 2: Solve for x and y

From (1), y = 19 - x. Substitute into (2):

x² + (19 - x)² = 193 x² + 361 - 38x + x² = 193 2x² - 38x + 168 = 0 ⇒ x² - 19x + 84 = 0 (x - 12)(x - 7) = 0

Thus, x = 12 and y = 7 (or vice-versa, which doesn't affect absolute differences).

Step 3: Calculate the New Mean

We need the mean of 4 numbers: x, y, x + y + 1, |x - y|. Substitute x = 12, y = 7: The numbers are 12, 7, (12+7+1), |12-7| = 12, 7, 20, 5. New Mean = (12 + 7 + 20 + 5)/(4) = (44)/(4) = 11.

Pattern Recognition

Statistics questions mapping x+y and x²+y² inherently hide a quadratic symmetric system (x+y)² - 2xy = x²+y². Solving for the roots immediately grants the discrete terms.

Chapter Mix

Class 11 Maths: Statistics

Reference Study Guides

More Statistics Previous-Year Questions — Page 5

Q12 jee_main_2024_31_jan_evening Mean and Variance
Let the mean and the variance of 6 observation a, b, 68, 44, 48, 60 be 55 and 194, respectively if a > b, then a + 3b is
  • A. 200
  • B. 190
  • C. 180
  • D. 210

Solution

Related Formula
Mean x = (Σ xᵢ)/(n) Variance σ² = Σ (xᵢ - x)²n
Core Logic

Mean is 55:

(a + b + 68 + 44 + 48 + 60)/(6) = 55 220 + a + b = 330 a + b = 110

Variance is 194:

((a-55)² + (b-55)² + (68-55)² + (44-55)² + (48-55)² + (60-55)²)/(6) = 194 (a-55)² + (b-55)² + 13² + (-11)² + (-7)² + 5² = 1164 (a-55)² + (b-55)² + 169 + 121 + 49 + 25 = 1164 (a-55)² + (b-55)² = 800

Expand the squares using a+b=110: a² + b² - 110(a+b) + 2(3025) = 800 a² + b² - 110(110) + 6050 = 800 a² + b² = 6850 Using (a+b)² = 12100 a²+b²+2ab = 12100 2ab = 12100 - 6850 = 5250. (a-b)² = a²+b² - 2ab = 6850 - 5250 = 1600 a-b = 40 (since a>b).

Solving a+b=110 and a-b=40:

a = 75, b = 35

Finally, evaluate a + 3b:

a + 3b = 75 + 3(35) = 180
Chapter Mix

Class 11 Maths: Statistics

More Statistics Questions — jee_main_2026_23_january_morning

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