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Aldehydes, Ketones and Carboxylic Acids appeared 46 times across 3 years — 5.3% of Chemistry. This question is from Cross-Aldol and Cannizzaro Reactions.

Year 2026 2025 2024 Total
Questions 14 21 11 46

The compound A, C₈H₈O₂ reacts with acetophenone to form a single product via cross-Aldol condensation. The compound A on reaction with conc. NaOH forms a substituted benzyl alcohol as

Solution & Explanation

Related Formula
Ar-CHO + conc. NaOH Cannizzaro Ar-CH₂OH + Ar-COO^-
Core Logic

Step 1: Compound A has molecular formula C₈H₈O₂ and undergoes Cannizzaro reaction with conc. NaOH A lacks α-hydrogen and is an aromatic aldehyde.

Step 2: Compound A is 4-methoxy benzaldehyde (CH₃O-C₆H₄-CHO).

Step 3: Cross-Aldol condensation with acetophenone yields a single aldol condensation product (B) structure.

Step 4: Cannizzaro reaction with conc. NaOH produces 4-methoxybenzyl alcohol and 4-methoxybenzoate anion.

Cross-aldol and Cannizzaro reaction diagram for Q68 - JEE Main 2026 Evening
Cross-aldol and Cannizzaro reaction diagram for Q68 - JEE Main 2026 Evening

Cross-aldol and Cannizzaro reaction diagram for Q68 - JEE Main 2026 Evening
Cross-aldol and Cannizzaro reaction diagram for Q68 - JEE Main 2026 Evening

Pattern Recognition

Sees: C₈H₈O₂ undergoing Cannizzaro to form substituted benzyl alcohol. Shortcut: Presence of -CHO without α-H and -OCH₃ ring substituent points directly to 4-methoxy benzaldehyde.

Chapter Mix

Class 12 Chemistry: Aldehydes, Ketones and Carboxylic Acids

Reference Study Guides

More Aldehydes, Ketones and Carboxylic Acids Previous-Year Questions — Page 10

Q jee_main_2024_31_jan_morning Reactions with Grignard Reagent
The product of the following reaction is P.
Reactions with Grignard Reagent diagram for Q84 - JEE Main 2024 Morning
The image shows p-hydroxybenzaldehyde reacting with one equivalent of PhMgBr followed by aqueous ammonium chloride.
The number of hydroxyl groups present in the product P is
Numerical Answer. Answer: 0 to 0

Solution

Core Logic

The given reactant is p-hydroxybenzaldehyde, which contains both a phenolic -OH group (acidic) and an aldehyde group (electrophilic).

When one equivalent of Grignard reagent (PhMgBr) is added, it behaves primarily as a strong base due to the presence of an acidic proton. Acid-base reactions are extremely fast compared to nucleophilic additions.

The acidic phenolic -OH reacts with PhMgBr:

PhMgBr + HO-C₆H₄-CHO arrow Ph-H (Benzene) + BrMg-O-C₆H₄-CHO

Upon workup with aq. NH₄Cl, the phenoxide ion simply regenerates the starting p-hydroxybenzaldehyde. However, the question asks for the number of hydroxyl groups present in the formed product (Benzene).

Reactions with Grignard Reagent diagram for Q84 - JEE Main 2024 Morning
The image shows p-hydroxybenzaldehyde reacting with one equivalent of PhMgBr followed by aqueous ammonium chloride.

The distinct product formed in the reaction is Benzene. Benzene has 0 hydroxyl groups.

Pattern Recognition

Whenever a Grignard reagent encounters a molecule with an acidic hydrogen (alcohol, phenol, amine, alkyne), it will invariably act as a base first. If only 1 equivalent is used, nucleophilic addition to carbonyls will NOT happen.

Chapter Mix

Class 12 Chemistry: Aldehydes, Ketones and Carboxylic Acids Class 12 Chemistry: Alcohols, Phenols and Ethers

More Aldehydes, Ketones and Carboxylic Acids Questions — jee_main_2026_22_january_evening

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