Let O be the vertex of the parabola x^2=4y and Q be any point on it. Let the locus of the point P, which divides the line segment OQ internally in the ratio 2: 3 be the conic C. Then the equation of the chord of C, which is bisected at the point (1, 2), is:

Solution & Explanation

### Related Formula textSection Formula: quad P = fracm cdot Q + n cdot Om + n textChord bisected at (x_1, y_1) : quad T = S_1 ### Core Logic Given parabola x^2 = 4y, its vertex O = (0, 0). A general point Q on x^2 = 4y is (2t, t^2). Let P(h, k) divide OQ in ratio 2:3. By section formula: h = frac2(2t) + 3(0)5 = frac4t5 k = frac2(t^2) + 3(0)5 = frac2t^25
Locus of point dividing parabolic chord for Q20 - JEE Main 2026 Morning
Locus of point dividing parabolic chord for Q20 - JEE Main 2026 Morning
### Step 1: Finding the Locus C From h = frac4t5, we get t = frac5h4. Substitute into k: k = frac25 left(frac5h4right)^2 = frac25 cdot frac25h^216 = frac5h^28 8k = 5h^2 Rightarrow 5x^2 = 8y So the conic C is the parabola 5x^2 = 8y. ### Step 2: Chord bisected at a point We need the equation of the chord of C: 5x^2 - 8y = 0 bisected at (x_1, y_1) = (1, 2). Use T = S_1. T = 5xx_1 - 4(y + y_1) = 5x(1) - 4(y + 2) = 5x - 4y - 8 S_1 = 5(1)^2 - 8(2) = 5 - 16 = -11 Equating T and S_1: 5x - 4y - 8 = -11 5x - 4y + 3 = 0 ### Pattern Recognition Internal division locus of a vertex chord on standard conic identically scales the conic. Once the child-conic is found, standard mid-point chord protocol (T=S_1) strictly applies algebraically. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Maths: Parabola Class 11 Maths: Straight Lines

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