Given below are two statements : Statement I : The number of pairs among [SiO_2, CO_2]$[SiO_{2}, CO_{2}]$, [SnO, SnO_2]$[SnO, SnO_{2}]$, [PbO, PbO_2]$[PbO, PbO_{2}]$ and [GeO, GeO_2]$[GeO, GeO_{2}]$, which contain oxides that are both amphoteric is 2. Statement II : BF_3$BF_{3}$ is an electron deficient molecule can act as a lewis acid, forms adduct with NH_3$NH_{3}$ and has a trigonal planar geometry. In the light of the above statement, choose the correct answer from the option given below.

### Core Logic Evaluating Statement I: - SiO_2$SiO_2$, CO_2$CO_2$, GeO$GeO$, GeO_2$GeO_2$ are acidic in nature. - SnO$SnO$, SnO_2$SnO_2$, PbO$PbO$, PbO_2$PbO_2$ are amphoteric in nature. Therefore, the pairs [SnO, SnO_2]$[SnO, SnO_2]$ and [PbO, PbO_2]$[PbO, PbO_2]$ contain oxides that are both amphoteric. Number of such pairs = 2. Statement I is True. Evaluating Statement II: - BF_3$BF_3$ has 6 electrons in the outermost shell of the central Boron atom. It is electron-deficient and acts as a Lewis acid. - It accepts a lone pair from Lewis bases like NH_3$NH_3$ to form an adduct. - In BF_3$BF_3$, Boron is sp^2$sp^2$ hybridized, resulting in a trigonal planar geometry. Statement II is True. ### Step 1: Conclusion Both statements are factually correct. ### Pattern Recognition Oxides of heavier Group 14 elements (Sn, Pb) are typically amphoteric in both their +2 and +4 oxidation states. BF_3$BF_3$ is the quintessential Lewis acid. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Chemistry: p-Block Elements Class 11 Chemistry: Chemical Bonding and Molecular Structure