MnO_4^2-$MnO_{4}^{2-}$, in acidic medium, disproportionates to :

### Related Formula 3mathrmMnO_4^2- + 4mathrmH^+ rightarrow 2mathrmMnO_4^- + mathrmMnO_2 + 2mathrmH_2mathrmO$$3\mathrm{MnO}_4^{2-} + 4\mathrm{H}^+ \rightarrow 2\mathrm{MnO}_4^- + \mathrm{MnO}_2 + 2\mathrm{H}_2\mathrm{O}$$ ### Core Logic Manganate ion (mathrmMnO_4^2-$\mathrm{MnO}_4^{2-}$), where Mn is in +6 oxidation state, is unstable in acidic medium and undergoes disproportionation. It oxidizes to Permanganate (mathrmMnO_4^-$\mathrm{MnO}_4^-$, +7 state) and reduces to Manganese dioxide (mathrmMnO_2$\mathrm{MnO}_2$, +4 state). ### Pattern Recognition Manganate (green, +6) disproportionates in acid to Permanganate (purple, +7) and MnO_2$MnO_2$ (brown/black precipitate, +4). ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: d and f Block Elements