Let z be the complex number satisfying |z-5|leq 3 and having maximum positive principal argument. Then 34left|frac5z-125iz+16right|^2 is equal to:

Solution & Explanation

### Related Formula textFor maximum argument of z text on a circle, the ray from origin is tangent to the circle. textIf |z-a| leq r, text maximum argument implies sintheta = fracr|a| text and coordinates are x=acos^2theta, y=asinthetacostheta ### Core Logic
Complex geometry maximum argument diagram for Q19 - JEE Main 2026 Evening
Complex geometry maximum argument diagram for Q19 - JEE Main 2026 Evening
The condition |z-5|leq 3 represents a disk centered at (5,0) with radius 3. To maximize the principal argument theta, the ray from origin must touch the circle in the first quadrant. The tangent, origin, and center form a right-angled triangle. ### Step 1: Locate the Point z From geometry, hypotenuse c = 5, opposite (radius) r = 3. The adjacent side (length of tangent) is sqrt5^2 - 3^2 = 4. The angle of tangency theta satisfies sintheta = frac35 and costheta = frac45. The point P(z) lies on the circle and the tangent ray: z equiv (4costheta, 4sintheta) = left(4left(frac45right), 4left(frac35right)right) = left(frac165, frac125right) z = frac165 + frac125i ### Step 2: Evaluate the Target Expression We need 34left|frac5z - 125iz + 16right|^2. Substitute 5z = 16 + 12i: Numerator: 5z - 12 = 16 + 12i - 12 = 4 + 12i Denominator: 5iz + 16 = i(16 + 12i) + 16 = 16i - 12 + 16 = 4 + 16i Expression: 34 left|frac4 + 12i4 + 16iright|^2 = 34 frac|4 + 12i|^2|4 + 16i|^2 = 34 frac4^2 + 12^24^2 + 16^2 = 34 left(frac16 + 14416 + 256right) = 34 left(frac160272right) = frac34 times 160272 = frac5440272 = 20 ### Pattern Recognition For maximum arg(z) on |z-c| = r where c is real, z coordinates are given by geometric projection: z = sqrtc^2-r^2(costheta + isintheta) where sintheta = r/c. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Maths: Complex Numbers

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